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osanseviero
 one year ago
Electric field question
osanseviero
 one year ago
Electric field question

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osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1There is an electrical field. There is a line with constant density. We know L (how long is the line). At a distance a from the middle, there is a point. Which is the field there? dw:1441428125288:dw

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1It is not infinite though, so I don't think we can use Gauss here

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Actually it does not say anything about the relationship between a and L

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0i don't know how to deal with the fringing effects the occur at the the end point of the line, i do know how to get the E field if the line if infinite, (good approximation if a<<L)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0hmm i maybe if a is a point above the MIDDLE of the line , the fringing effect from both sides cancel

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1It is in the middle

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1So I would guess that in horizontal all of them cancel

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441430062457:dw

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1So I would have to use Gauss?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0yeah use this cylinder as your gaussian pill box

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Doing that I have E(2pi*a*L) = Qin / epsilon. But they told me doing this was not correct

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0is Qin the total charge of the line?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0i think you have to express the charge in terms of a linear charge density \(\lambda\) \[\lambda = q/L\]

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1E = lambda/(2 * pi * a * Eo) (Eo is the epsilon)

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1But still...how would you solve this without Gauss?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0you mean like using Coulombs law?

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Yep. Coulomb + Electric field

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1And charge distributions

osanseviero
 one year ago
Best ResponseYou've already chosen the best response.1Found an answer, thanks a lot
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