anonymous
  • anonymous
sand is poured on a conical pile at a rate of 20 m^3/min. The height of the pile is always equal to the radius of the base of the pile. When the pile is 3m high, how fast is the height of the pile increasing?
Mathematics
katieb
  • katieb
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imqwerty
  • imqwerty
dv/dt=20 m^3/minute we r given that radius=height, so radius=3=heoght :) Volume of cone=1/3(πr^2h) now Volume=1/3π9h dv/dt=1/3(9)dh/dt dv/dt=3dh/dt dv/dt=3dh/dt we know that dv/dt=20 so 20=3dh/dt dh/dt=20/3
anonymous
  • anonymous
how did you get the now volume?
anonymous
  • anonymous
oh it's radius sorry :))

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anonymous
  • anonymous
*the
imqwerty
  • imqwerty
it is given in the question that height of pike is ALWAYS equal to radius of pile :)
imqwerty
  • imqwerty
*pile
anonymous
  • anonymous
why was the π gone in dv/dt=1/3(9)dh/dt? :)
anonymous
  • anonymous
imqwerty
  • imqwerty
yea pi shuld also come sry
anonymous
  • anonymous
the answer should be 20/3π? :)
imqwerty
  • imqwerty
yea
anonymous
  • anonymous
oh it's not in the choices :(
imqwerty
  • imqwerty
what r the choices?
anonymous
  • anonymous
the choices are : 1.42, 0.71, 0.66 and 1.32
imqwerty
  • imqwerty
something went wrng jst a min
anonymous
  • anonymous
oh it's supposed to be 20/9π :)
anonymous
  • anonymous
dv/dt = 1/3πr^(3)
imqwerty
  • imqwerty
how?
anonymous
  • anonymous
|dw:1441469657321:dw|
anonymous
  • anonymous
dv/dt = πr^(2)dh/dt
imqwerty
  • imqwerty
:O okay :)
anonymous
  • anonymous
dv/dt = π(9) dh/dt then plug in 20 for dv/dt
anonymous
  • anonymous
thank you guys for helping me :)
imqwerty
  • imqwerty
no prblm :D

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