I meant if AB, CD are in plane1, is there the case of AB, CD are in plane2 which is different from plane1
well if a line lies on x-y plane we wuld write it as- ax+by+c=0 nd if it is on x-z plane we wuld write it as ax+bz+c=0 so u can get the same eq....
I don't get it, please, explain more.
and what is nd ? on "nd if it is....."
ok the standard form of a line present in x-y plane is- ax+by+c=0 u can write it as - -ax-by=c x/(c/-a)+y/(c/-b)=1 where c/-a = x intercept c/-b = y intercept
similarly if u go with x-z axes
u have the standard line equation as ax+bz+c=0 u can write it as- x/(c/-a) + z/(c/-b) =1 nd the intercepts culd be the same in both cases so the equations can be similar but they will differ cause they r jst in diff planes
So, it is false, right? there is not the case of if AB, CD are in plane 1, they cannot be in plane2 which is different from plane 1, right?
I appreciate your help, but it will be perfect if you use standard English instead of the "teen language" since I am not a native one. I cannot understand all of the teen words. :)