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rock_mit182
 one year ago
Please someone help to figure this out:
the problem says that the force between two spheres is 4N they're separeted by 10 cm. If the distance is two times less the initial what will happen with the magnitud of the force between them.
columb's laws = F =k\frac{ q*q }{ r^2 }
rock_mit182
 one year ago
Please someone help to figure this out: the problem says that the force between two spheres is 4N they're separeted by 10 cm. If the distance is two times less the initial what will happen with the magnitud of the force between them. columb's laws = F =k\frac{ q*q }{ r^2 }

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rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0\[4 = k \frac{ q*q }{r^2 } \]

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.00,1 meters for the initial values

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0now if the radius is multiplied by 1/2

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0the radius would be 1/20, right ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea you got it keep going

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0i think the right options are 8N or 16 N

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0because r is squared, right ?

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0now if de charge of the two spheres is two times each one, mantaining the initial radius an force, the answer would be the same ?

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0\[4 = k \frac{ 2q*2q }{ (0,1)^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so the initial force between the two charges separated by a distance d is F = 2kQ2 / d2 . After touching, the charges become Q/2 and 5Q/4 and the force is 5kQ2 / 8d2 = 5F / 16 . so the answer would be 5F / 16

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0did you see my last equation ?

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0i curious about what just did happen

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0\[4 =k \frac{ 2q *2q }{ (0,1)^2 }\]

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0F1 =2 so F2 = ? ; keeping in mind that Im using the initial values but double charge ( each one)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oka what is the question asking? id dont see

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0F2 is incresing respect to one by a factor of ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it multiple choice i think its increasing by 2 but im not sure you might wanna ask someone else for a second opinion

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0and i think is by a factor of 4

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0anyway thanks a lot for helping me out

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0@IrishBoy123 any thoughts ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1you have an inverse square relationship here so you can say \(\large F = \frac{C}{r^2} \) where C is a constant ie, \(\large C = F \ r^2\) so, applying this: \(\large C = 4 \times 10^2 = F \times 5^2\) what is F? [PS "two times less the" doesn't mean very much so i assumed you meant distance is halved]

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0yeah that is what i meant

rock_mit182
 one year ago
Best ResponseYou've already chosen the best response.0distance is halved

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1so \[4 \times 10^2 = ?? \times 5^2\]
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