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anonymous

  • one year ago

Assume a tractor has an initial price of $1000.00 and sells for $100.00 after 23 years. Assume that the tractor’s value depreciates linearly with the passing years. Let V represent the tractor's value in dollars and let t represent the number of years since the tractor was purchased. Write a formula to express the tractor's value as a function of time: V(t)=

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  1. anonymous
    • one year ago
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    I know that V(t)= 1000-39.13t

  2. anonymous
    • one year ago
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    And I know that the vertical intercept of the value function V(t)= 1000 BUT I'm confused on how to get the horizontal intercept

  3. kropot72
    • one year ago
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    The horizontal intercept is found by plugging in zero for the value of V(t) and solving to find the value of t: 0 = 1000 - 39.13t ............(1) Now solve equation (1) to find the number of years for the tractor have zero value.

  4. anonymous
    • one year ago
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    t= -25.5558

  5. anonymous
    • one year ago
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    Now what?

  6. anonymous
    • one year ago
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    @zepdrix Can you help? :)

  7. kropot72
    • one year ago
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    There is an error in your solution. How did you get the negative sign?

  8. kropot72
    • one year ago
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    0 = 1000 - 39.13t ............(1) Add 39.13t to both sides. This gives: 39.13t = 1000 Now divide both sides by 39.13, to get the value of t in years. Then round to result.

  9. anonymous
    • one year ago
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    Ah, I see. Thanks! 25.56 (y)

  10. kropot72
    • one year ago
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    You're welcome :)

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