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anonymous
 one year ago
Find the area and perimeter. (Drawing will be post in Comment)
anonymous
 one year ago
Find the area and perimeter. (Drawing will be post in Comment)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441474437167:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441474560262:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441474590229:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait let me calculate the area.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1The first image that you have shown is a composite figure, meaning that it is made up of many different shapes. I have divided the shape into simpler figures so that you can easily find the area of each divided shapes and then add it all together to get the final area. The perimeter should be fairly easy as well because you just have to add all of the measurements of the sides together.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441474779558:dw I juts labeled all of the divided figures for an easier time to calculate the areas.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441474799967:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1For figure C, you have to multiply 15 x 3. Does that equal to 30, like you said?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441474915511:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Yes that is now correct. You need to now add up all of the areas of figures A, B, and C.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441474983967:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Great! That is the area of the first figure: 111m^2. Now for the perimeter add up all of the side measurements dw:1441475068227:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441475085978:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441475172755:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Add the 6m as well because we forgot the other missing side length.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh Ok thanks ^_^ Can you please help me to other picture above?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Area of trapezoid: \[\large \frac{ 1 }{ 2 }(b_1 + b_2)\times h\]

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441475363048:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you wait? I gotta go eat.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1A side note, the b_1 and the b_2 in the formula can be either one. There is no certain designation because it will equal to the same thing once you add it (according to the commutative property of addition).

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1I am sorry, I cannot. I have to go soon.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@calculusxy I'm back :))

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Great :) Now did you find the area.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait, how can i find the area? There's 2 base

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1Did you look at the picture and the formula that I gave you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohh ok i got this. :D Check my answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yay! :D Thanks for everything @calculusxy ^_^ I learned something.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1No problem :) And I always happy to teach and learn from users, like you.

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.1*And I AM always happy to teach and learn from users, like you.
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