anonymous
  • anonymous
Given the linear programming problem, use the method of corners to determine where the minimum occurs and give the minimum value minimize C=x+3y Subjectto x less than equal to 3 y less than equal to 5 x greater then equal to 0 y greater to equal than 0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Did you draw this?
anonymous
  • anonymous
Im not sure how to ... I can read a graph already drawn but creating one myself is a different story.
anonymous
  • anonymous
Let's start with this.|dw:1441475021450:dw|

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anonymous
  • anonymous
\(y \ge 0\) is everything above x-axis|dw:1441475235023:dw|
anonymous
  • anonymous
and \(x \ge 0\) is everything right of the y-axis
anonymous
  • anonymous
Then for \(y \le 3\) shade everything below the line \(y=3\)|dw:1441475376673:dw|
anonymous
  • anonymous
\(x \le 5\) is left of the line x = 5|dw:1441475429193:dw|
anonymous
  • anonymous
So your corners are the corners of the black rectangle above, where all 4 inequalities are valid
anonymous
  • anonymous
Write the coordinates of those 4 corners then test them all in the constraint \(C=x+3y\) to find the smallest
anonymous
  • anonymous
so it would 0,3 and 5,0?
anonymous
  • anonymous
yes, those are two of the corners. (0, 0) and (5, 3) are the others

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