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anonymous

  • one year ago

Converting a equation of a circle in standard form to find center points and radius: Okay so the equation is x^2-7x+y^2+10y+16=0. I already solved the left side of the equation (x-7/2)^2+(y+5)^2 so my center is (7/2, -5) but once I moved the 16 to the right so that it's =-16 am not quite sure what to do now .... ? Help am so close.

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  1. anonymous
    • one year ago
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    you missed while completing the square note: the number 16 will add to other quantities so the final equation has not 16

  2. anonymous
    • one year ago
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    Am not quite sure what you mean.... and I know the final product isn't 16 but that's why am not sure what to do with it :( @esamalaa

  3. anonymous
    • one year ago
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    you can write your solution steps and i will find errors for you

  4. anonymous
    • one year ago
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    \[X ^{2}-7x+Y ^{2}+10y+16=0\]

  5. anonymous
    • one year ago
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    ok what is the first step ?

  6. anonymous
    • one year ago
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    Sorry its taking me forever. .... my laptop keeps on stalling and I just moved to my phone..... @esamalaa

  7. anonymous
    • one year ago
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    X^2 - 7X + y^2 +10y=-16

  8. anonymous
    • one year ago
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    X^2-7x+(7/2)^2. +y^2+10y+(10/2)^2

  9. anonymous
    • one year ago
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    (X-7/2)^2 + (y+5)^2 = -16

  10. anonymous
    • one year ago
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    Center (7/2, -5)

  11. anonymous
    • one year ago
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    =-16 +7/2 -5 <<<<< is this what am suppose to do next?

  12. anonymous
    • one year ago
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    @esamalaa

  13. anonymous
    • one year ago
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    -16 +(7/2)^2+25

  14. anonymous
    • one year ago
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    Ohhh is it 85/4 ??? @esamalaa

  15. anonymous
    • one year ago
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    yes but that is the radius squared if you want the radius itself take the sq root for 85/4

  16. anonymous
    • one year ago
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    Yay ! So if I did it the other way would it be 2.304..... ? @esamalaa

  17. anonymous
    • one year ago
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    4.60

  18. anonymous
    • one year ago
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    Oh ok I see ! Yay ! Thank you so much, am new to this fourm and you have been a big help ! God Bless You ! @esamalaa

  19. anonymous
    • one year ago
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    anytime

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