anonymous
  • anonymous
Converting a equation of a circle in standard form to find center points and radius: Okay so the equation is x^2-7x+y^2+10y+16=0. I already solved the left side of the equation (x-7/2)^2+(y+5)^2 so my center is (7/2, -5) but once I moved the 16 to the right so that it's =-16 am not quite sure what to do now .... ? Help am so close.
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
you missed while completing the square note: the number 16 will add to other quantities so the final equation has not 16
anonymous
  • anonymous
Am not quite sure what you mean.... and I know the final product isn't 16 but that's why am not sure what to do with it :( @esamalaa
anonymous
  • anonymous
you can write your solution steps and i will find errors for you

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anonymous
  • anonymous
\[X ^{2}-7x+Y ^{2}+10y+16=0\]
anonymous
  • anonymous
ok what is the first step ?
anonymous
  • anonymous
Sorry its taking me forever. .... my laptop keeps on stalling and I just moved to my phone..... @esamalaa
anonymous
  • anonymous
X^2 - 7X + y^2 +10y=-16
anonymous
  • anonymous
X^2-7x+(7/2)^2. +y^2+10y+(10/2)^2
anonymous
  • anonymous
(X-7/2)^2 + (y+5)^2 = -16
anonymous
  • anonymous
Center (7/2, -5)
anonymous
  • anonymous
=-16 +7/2 -5 <<<<< is this what am suppose to do next?
anonymous
  • anonymous
@esamalaa
anonymous
  • anonymous
-16 +(7/2)^2+25
anonymous
  • anonymous
Ohhh is it 85/4 ??? @esamalaa
anonymous
  • anonymous
yes but that is the radius squared if you want the radius itself take the sq root for 85/4
anonymous
  • anonymous
Yay ! So if I did it the other way would it be 2.304..... ? @esamalaa
anonymous
  • anonymous
4.60
anonymous
  • anonymous
Oh ok I see ! Yay ! Thank you so much, am new to this fourm and you have been a big help ! God Bless You ! @esamalaa
anonymous
  • anonymous
anytime

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