The electron configuration of calcium is A. 1s22s22p23s23p34s2. B. 1s22s22p103s23p4. C. 1s22s23s23p63d8. D. 1s22s22p63s23p64s2

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The electron configuration of calcium is A. 1s22s22p23s23p34s2. B. 1s22s22p103s23p4. C. 1s22s23s23p63d8. D. 1s22s22p63s23p64s2

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id be grateful if someone could explain how to do this as well
D. for sure
check some youtube videos loke this one: https://www.youtube.com/watch?v=8XfMkBwYqC4

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@moudown828 are you familiar with energy levels/filling orbitals?
\(Electronic~ configuration~ of ~Calcium ~(Ca)\) Atomic number of calcium = 20 Therefore number of electrons = 20 Thus, electronic configuration of calcium is |dw:1441540508433:dw| Thus, Number of orbit in calcium = 4 So, which is your Answer ? @moudown828
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Did you Get 1s2 2s2 2p6 3s2 3p6 4s2. ? @moudown828
|dw:1441544690430:dw| here are the limit values of your s,p,d, and f : s=2 p=6 d=10 f=14, the atomic number for calcium is 20. so following the pattern, the answer should be 1s2 2s2 2p6 3s2 3p6 4s2. when you add it the sum would be 2+2+6+2+6+2 = 20 which is the atomic number for calcium.
|dw:1441545260354:dw| the pattern should be like a zig zag line
@martaamador62 you are an artist for sure..
http://www.tutorvista.com/content/chemistry/chemistry-iii/atomic-structure/electronic-configuration.php check this out @moudown828

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