If z=1+i, then the magnitude of z is sqrt(2). What is the phase angle of z?

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If z=1+i, then the magnitude of z is sqrt(2). What is the phase angle of z?

Mathematics
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Tan y/x. Book says 1, isnt it real/imag? How did they get that?
I know they got the mag. by mult. by conjugate.
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Just set up a triangle I guess :)
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Hum. Ok. The book just says use y/x (pchem book). If z=x+iy, and the mag is sqrt 2, can you not just say y/x?
It says =1 which in angle terms is 45.
Yes, but I thought you were having trouble with it conceptually :P so i went into a little more detail lol
Thanks for that! I actually understand the graph! Been doing Pchem all day and brain fried.
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Therefore: \(\large\rm arctan\left(\frac{y}{x}\right)=\theta\)
Ya I guess we gotta be careful with our y, right? We're thinking of our complex number \(\large\rm z=x+iy\) So the i is not included in the y. It's just the distance in that direction. So ya y=1, good good
arctan (1/1) does not give 45 degrees though.
no? :o it should. are you in radians, maybe it's spitting out pi/4 as a decimal value
Bless you, Zepdrix.
silly bus -_- we're gonna downgrade you to a shortbus some day
I need to be.
XD

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