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Would i subtract 1 to the other side or subtract it with 4 first?
the -4 is being multiply to |n+2| so u cant subtract 1frm the -4.... however you can subtract 1 frm both sides of the inequality to get -4|n+2|<-23-1
But i'm supposed to isolate the absolute value first.
Would i divide -4?
after that we can divide both sides by -4
wat do we get?
n+2< -24/4 -> n+2<-6
then we subtract 2 with -6 so n<-4 right?
what? |n+2|<-24/4 |n+2|<6 we now get rid of the absolute value be spliting the inequality ... making 1positive and 1negative ..like this (n+2)<6 and (n+2)<-6 we now solve for n
that shd be -24/-4 ** (error +4)
so n+2<6 n<6-2 and n+2<-6 n<-6-2
Oh i see what you did :O so n<-4 and n<-8. How would this be graphed?
oh whoops i put -4 instead of 4
n>4 and n<-8
|dw:1441506974345:dw|more like this^^
This is kind of different to what my teacher taught... Example: 3|b+8|-10<5 then make a negative equation: -3|b+8|-10>5 +10 +10 (signs are switched) +10 +10 ----------- ----------- 3|b+8|<15 -3|b+8|>15 ---------- ----------- 3 -3 b+8<5 b+8>-5 -8 -8 -8 -8 ------- ----------- b<-3 b>-13
Oh :P should have saw what you typed before what i typed. I see, thanks for the help though.
yes it shd be n+2>6 and n+2<-6 i made and error not switching the first sign shd be n+2>6 n>4 and n<-8
So how would you make 1-4|n+2|<-23 into a positive?
im not sure i understand what ur asking...?
like my example
There is an error in the example the 2nd equation should have been 5 instead of -5 to be equaled to -15 when adding -10.
*should have been -5 instead of 5
no its correct
Alright then :D Thanks for the help.
-3|b+8|-10>5 then we add 10 to bot sides we get -3|b+8|>5+10
we then divide both sides by -3 to get |b+8|>10/-3
10+5 = 15
yes correct tpye error
It's fine you don't have to say anymore i understand what you mean. Thanks for the time to help me @LynFran :)