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clamin

  • one year ago

PLEASE HELP!! MEDAL!! y=1/2x^2-4x+10 please show me the x and y intercept...

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  1. clamin
    • one year ago
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    i dont know how if theres a fracton

  2. zepdrix
    • one year ago
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    Should that be -10 on the far right side?

  3. zepdrix
    • one year ago
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    So it looks like this?\[\large\rm y=\frac{1}{2}x^2-4x-10\]

  4. clamin
    • one year ago
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    its +10 @zepdrix

  5. zepdrix
    • one year ago
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    \[\large\rm y=\frac{1}{2}x^2-4x+10\]Ok so like... to find y-intercepts... We want to know where this function intercepts the y-axis. That happens when x=0.\[\large\rm y=\frac{1}{2}\cdot0^2-4\cdot0+10\]So what do you get for your x-intercept? :o

  6. zepdrix
    • one year ago
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    For your y-intercept I mean* >.<

  7. zepdrix
    • one year ago
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    The 0's should make this step nice and easy.

  8. clamin
    • one year ago
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    10

  9. zepdrix
    • one year ago
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    cool first part done \c:/

  10. zepdrix
    • one year ago
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    The function will cross the x-axis when the y coordinate is zero. \[\large\rm 0=\frac{1}{2}x^2-4x+10\]I also don't like fractions. I would recommend multiplying both sides by 2.\[\large\rm 2\cdot0=2\cdot\left(\frac{1}{2}x^2-4x+10\right)\]

  11. zepdrix
    • one year ago
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    \[\large\rm 0=x^2-8x+20\]Do you understand what that did? :o The left side is still 0, everything on the right doubled.

  12. clamin
    • one year ago
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    yes

  13. clamin
    • one year ago
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    so im gonna use that instead of 1/2??

  14. zepdrix
    • one year ago
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    I multiplied by 2 because the fraction had a 2 in the denominator. So no more fraction! Yay! Yes, use this equation instead. Do you remember how to factor and stuff? :)

  15. clamin
    • one year ago
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    yes

  16. clamin
    • one year ago
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    so whatever denominator thats what your gonna multiply to get rid of fractions??

  17. zepdrix
    • one year ago
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    Yes! But if you have multiple fractions showing up in the same equation, then it becomes a little trickier. Then you would have to multiply by the Least Common Multiple of those denominators.

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