1. clamin

i dont know how if theres a fracton

2. zepdrix

Should that be -10 on the far right side?

3. zepdrix

So it looks like this?$\large\rm y=\frac{1}{2}x^2-4x-10$

4. clamin

its +10 @zepdrix

5. zepdrix

$\large\rm y=\frac{1}{2}x^2-4x+10$Ok so like... to find y-intercepts... We want to know where this function intercepts the y-axis. That happens when x=0.$\large\rm y=\frac{1}{2}\cdot0^2-4\cdot0+10$So what do you get for your x-intercept? :o

6. zepdrix

For your y-intercept I mean* >.<

7. zepdrix

The 0's should make this step nice and easy.

8. clamin

10

9. zepdrix

cool first part done \c:/

10. zepdrix

The function will cross the x-axis when the y coordinate is zero. $\large\rm 0=\frac{1}{2}x^2-4x+10$I also don't like fractions. I would recommend multiplying both sides by 2.$\large\rm 2\cdot0=2\cdot\left(\frac{1}{2}x^2-4x+10\right)$

11. zepdrix

$\large\rm 0=x^2-8x+20$Do you understand what that did? :o The left side is still 0, everything on the right doubled.

12. clamin

yes

13. clamin

so im gonna use that instead of 1/2??

14. zepdrix

I multiplied by 2 because the fraction had a 2 in the denominator. So no more fraction! Yay! Yes, use this equation instead. Do you remember how to factor and stuff? :)

15. clamin

yes

16. clamin

so whatever denominator thats what your gonna multiply to get rid of fractions??

17. zepdrix

Yes! But if you have multiple fractions showing up in the same equation, then it becomes a little trickier. Then you would have to multiply by the Least Common Multiple of those denominators.