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En

  • one year ago

prove the formula: arccos x=1/2pi- arcsin x please i still dont get it

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  1. EmmaTassone
    • one year ago
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    do you know a bit of calculus?

  2. En
    • one year ago
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    yep :) i'm solving bunch of problems .. i just dont get this one.. :/

  3. En
    • one year ago
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    sorry for the trouble :)

  4. EmmaTassone
    • one year ago
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    \[-\frac{ 1 }{ \sqrt{1-x²} }+\frac{ 1 }{ \sqrt {1-x²} }=0\] \[\int\limits_{}^{}-\frac{ 1 }{ \sqrt{1-x²} } dx+\int\limits_{}^{}\frac{ 1 }{ \sqrt {1-x²} }dx=0\] \[\arccos(x)+\arcsin(x)+\delta =0\] Where delta is a constant, evaluating in zero: \[\arccos(0)+\arcsin(0)+\delta=0\] \[\frac{ \pi }{ 2 } + \delta =0\] \[\delta = -\frac{ \pi }{ 2 }\] \[\arccos(x) + \arcsin(x) -\frac{ \pi }{ 2 }= 0\] Finally; \[\arccos(x)= \frac{ \pi }{ 2 }- \arcsin(x)\]

  5. EmmaTassone
    • one year ago
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    no problem ts not trouble xD

  6. EmmaTassone
    • one year ago
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    althought this demonstration is not general at all, if you look I choose arccos(0)=pi/2 but i could had chosen arccos(0)=3pi/2 ,5pi/2 , etc..

  7. En
    • one year ago
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    thanks :)))

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