anonymous
  • anonymous
Iron-59 has a half-life of 45.1 days. How old is an iron nail if the Fe-59 content is 25% that of a new sample of iron?
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
25=100 e^(-.693 t/45.1) Ln(25)=ln(100) -.693 t/45.1 ln(25)-ln(100)=-.693 t/45.1 ln(25/100)=-.693t/45.1 t= - 45.1/.693 ( ln .25) t=90.2 days I put and it was wrong
anonymous
  • anonymous
@TacianaCampbelll Let me try... Ln(25)=ln(100) -.693 t/45.1 ln(25)-ln(100)=-.693 t/45.1 ln(25/100)=-.693t/45.1 t= - 45.1/.693 ( ln .25) t=90.2 days. \(\checkmark\) Is Correct !!
Arihangdu
  • Arihangdu
How this happen!!!!

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