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shamil98
 one year ago
Solve algebraically.
\[\frac{ e^x + e^{x} }{ e^x  e^{x} } = 5\]
I started out by multiply both sides by the bottom fraction and whatnot and took the natural logs of both sides and resulted in error.. haven't done math in months..
shamil98
 one year ago
Solve algebraically. \[\frac{ e^x + e^{x} }{ e^x  e^{x} } = 5\] I started out by multiply both sides by the bottom fraction and whatnot and took the natural logs of both sides and resulted in error.. haven't done math in months..

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ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1let \(e^x=u\), rearrange the equation and get a quadratic

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441511606981:dw

shamil98
 one year ago
Best ResponseYou've already chosen the best response.0Yeah that's what i did originally ^

shamil98
 one year ago
Best ResponseYou've already chosen the best response.0@ganeshie8 i'll try that right now

dan815
 one year ago
Best ResponseYou've already chosen the best response.2ya thats good enuff too

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441511696871:dw

shamil98
 one year ago
Best ResponseYou've already chosen the best response.0thanks guys forgot that e^x = 1/e^x xD

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1if you're not really interested in the numeric value, you could save all that algebra by simply saying \(\coth x = 5 \implies x = \coth^{1}(5)\)
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