shamil98
  • shamil98
Solve algebraically. \[\frac{ e^x + e^{-x} }{ e^x - e^{-x} } = 5\] I started out by multiply both sides by the bottom fraction and whatnot and took the natural logs of both sides and resulted in error.. haven't done math in months..
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ganeshie8
  • ganeshie8
let \(e^x=u\), rearrange the equation and get a quadratic
triciaal
  • triciaal
|dw:1441511606981:dw|
shamil98
  • shamil98
Yeah that's what i did originally ^

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shamil98
  • shamil98
@ganeshie8 i'll try that right now
dan815
  • dan815
ya thats good enuff too
dan815
  • dan815
|dw:1441511754857:dw|
dan815
  • dan815
|dw:1441511833267:dw|
shamil98
  • shamil98
OH
shamil98
  • shamil98
IM DUMB
triciaal
  • triciaal
|dw:1441511696871:dw|
shamil98
  • shamil98
thanks guys forgot that e^-x = 1/e^x xD
ganeshie8
  • ganeshie8
if you're not really interested in the numeric value, you could save all that algebra by simply saying \(\coth x = 5 \implies x = \coth^{-1}(5)\)
ganeshie8
  • ganeshie8
http://mathworld.wolfram.com/HyperbolicCotangent.html

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