## A community for students. Sign up today

1. clamin

$\sqrt{2x+15}=\sqrt{6-x}$

2. hartnn

try squaring both sides first to eliminate the square root on both sides.

3. clamin

after that do i solve the like terms?? @hartnn

4. hartnn

$$\Large (\sqrt{☺})^2=☺$$ yes, thats correct

5. clamin

$-27=-9\sqrt{n+3}$

6. hartnn

start by dividing -9 from both sides...

7. clamin

|dw:1441514393453:dw|

8. hartnn

yes! now you can square both sides :)

9. clamin

my answer is 6

10. hartnn

correct :)