A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing


  • one year ago

The moon's mass is approximately 1% of the earth's mass. How does the gravitational pull of the earth on the moon compare with the gravitational pull of the moon on the earth?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Let Mass of Earth be Me Mass of Moon Mm Gravitational Pull of Earth Fe and Gravitational Pull of Moon Fm \[M_{e},M_{m},F_{e},F_{m}\] These are the quantities Now the gravitational pull is proportional to the mass of the body so \[F \propto M\] Removing the proportionality we introduce a constant k \[F=kM\] Now for earth and moon we have the equations \[F_{e}=kM_{e}\] \[F_{m}=kM_{m}\] Dividing these we get \[\frac{F_{e}}{F_{m}}=\frac{M_{e}}{M_{m}}\] From this we get \[F_{m}=\frac{M_{m}}{M_{e}}.F_{e}\] But you are also given Mm as 1% of Me so \[M_{m}=\frac{1}{100}.M_{e} \implies M_{e}=100M_{m}\] Substitute this value in equation for Fm and simplify

  2. Melodious
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can explain this to me pls @Nishant_Garg

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...


  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.