## Melodious one year ago The moon's mass is approximately 1% of the earth's mass. How does the gravitational pull of the earth on the moon compare with the gravitational pull of the moon on the earth?

1. anonymous

Let Mass of Earth be Me Mass of Moon Mm Gravitational Pull of Earth Fe and Gravitational Pull of Moon Fm $M_{e},M_{m},F_{e},F_{m}$ These are the quantities Now the gravitational pull is proportional to the mass of the body so $F \propto M$ Removing the proportionality we introduce a constant k $F=kM$ Now for earth and moon we have the equations $F_{e}=kM_{e}$ $F_{m}=kM_{m}$ Dividing these we get $\frac{F_{e}}{F_{m}}=\frac{M_{e}}{M_{m}}$ From this we get $F_{m}=\frac{M_{m}}{M_{e}}.F_{e}$ But you are also given Mm as 1% of Me so $M_{m}=\frac{1}{100}.M_{e} \implies M_{e}=100M_{m}$ Substitute this value in equation for Fm and simplify

2. Melodious

can explain this to me pls @Nishant_Garg