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finally you have started reviewing epsilon delta!

Looks like it :P

I would think you would start off by making this equation:
-0.1<5x-5<0.1

then solving for x
-0.1<5x-5<0.1
+5 +5 +5
-------------
4.9<5x<5.1
/5 /5 /5
---------
0.98

0.98

right

so \(\delta = 0.02\) works

so you don't need to subtract from whatever the value of a is? (which in this problem, it's 2)

a graph might help
you want to spend some time and see whats going on

or you may continue with rest of the problems and hope things become clear after doing few problems

^ agreed. But this problem that preceded...I was able to get it with no problem. my process looked like this:
-0.1<5x-10<0.1
+10 +10 +10
------------------
9.9<5x<10.1
/5 /5 /5
----------
1.98

let me ask you a question there

Sure

you have
```
1.98

yes

that is wrong
how can both give you 0.02 ?
double check

wait...

2.02-2=0.02
2-1.98=0.02
^^
they both do give 0.02 o-o

Oops sry, you're right!

so it seems the same \(\delta\) works in both cases

yeah :P weird how the solutions are exactly the same, regardless of the functions being different

Why is that? do you know?

they both are kinda same functions, they only differ by a constant

f(x) = 5x-5
g(x) = 5x-10

that's true...I suppose that makes sense, thy only vary by where in the graph they start

teamviewer ?

o-o pardon?

you don't have teamviewer/skype?

nope

I could screenshot you what I'm looking at o-o

not necessary, i have a khan academy video that explains exactly this
one sec..

omg @ganeshie8 that's actually a super clear explanation, I got it! Thank you u.u