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En
 one year ago
PLEASE HEEEEELLLP!!!
pls view it from the attachment. :)
En
 one year ago
PLEASE HEEEEELLLP!!! pls view it from the attachment. :)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What do you need help with?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1x^4 is divided to both the terms of the numerator

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441522345977:dw dw:1441522367269:dw and all other terms remain as is

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\rm \frac{\frac{2x^3}{\sqrt{1x^4}}2x \arcsin(x^2)}{x^4}=\frac{\frac{2x^3}{\sqrt{1x^4}}}{x^4}\frac{2x \arcsin(x^2)}{x^4}\] \[\large\rm =\frac{2x^3}{x^4\sqrt{1x^4}}\frac{2x \arcsin(x^2)}{x^4}\] Do you understand these two steps?

En
 one year ago
Best ResponseYou've already chosen the best response.0OKAY ! I GET IT NOW. THANKS!

En
 one year ago
Best ResponseYou've already chosen the best response.0So you just multiply x^4 with sqrt(1+x^4) ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1you solve like terms \(\large\rm =\frac{2\color{blue}{x^3}}{\color{blue}{x^4}\sqrt{1x^4}}\frac{2\color{blue}{x} \arcsin(x^2)}{\color{blue}{x^4}}\) and no need to touch other terms...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1multiplying x^4 with sqrt(1x^4) will not have benefit for simplification

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, for simplicity, consider \(\sqrt {1x^4} =A\) dw:1441524054343:dw
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