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anonymous
 one year ago
You have 10 lb of CO2 in a 20 ft3
fire extinguisher at 30 o
C. Assuming the ideal gas
law holds, what will be the gauge pressure (psig) on the tank when full?
anonymous
 one year ago
You have 10 lb of CO2 in a 20 ft3 fire extinguisher at 30 o C. Assuming the ideal gas law holds, what will be the gauge pressure (psig) on the tank when full?

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Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Use PV=nRT equation P= Pressure in Nm^2 V= volume in cubic meters ( So we have to convert it ) n= No. of moles R= universal gas constant T= temperature in Kelvin. ( Since we are given it with Celsius We have to convert that ) Since we aren't given with the no. of moles. We can find no. of moles by mass of CO2 divided by molar mass of CO2 But substitute mass of CO2 should be substituted in grams. SO u have to convert it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have used this but my answer is 64.39 psig but the correct answer should be 51.3 psig :( @Rushwr

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1oh wait here the unit we have to use is psig right? ah then we have to convert the temperature to kelvin and Volume to cubic meters only !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have converted ft3 to L and i have also used 0.0821 L atm/K mol for R

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441548682633:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0P = 4.53 atm (14.22 psig/1atm) = 64.42 psig

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does my solution seem right? :(

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.11lb = 453.592g SO \[n = \frac{ 10 * 453.592g }{ 44gmol ^{1} } = 103.1mol\] \[R = 8.314 JK ^{1}mol ^{1}\] T = 273 +30 = 303K 1ft^3 = 0.028 m^3 So V= 20 * 0.028m^3 = 0.56m^3

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1then convert it and see !

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1That's what I got too I think that's wrong again ! COnvert and see ! I'll check more !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what unit is P ? atm?

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Yeah that's what I got too !!!!!!!!! Wondering !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmm maybe my professor got it wrong i don't know ¯\_(ツ)_/¯ :)). I'll just ask him. Thank you so much for helping me :D
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