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anonymous

  • one year ago

You have 10 lb of CO2 in a 20 ft3 fire extinguisher at 30 o C. Assuming the ideal gas law holds, what will be the gauge pressure (psig) on the tank when full?

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  1. Rushwr
    • one year ago
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    Use PV=nRT equation P= Pressure in Nm^-2 V= volume in cubic meters ( So we have to convert it ) n= No. of moles R= universal gas constant T= temperature in Kelvin. ( Since we are given it with Celsius We have to convert that ) Since we aren't given with the no. of moles. We can find no. of moles by mass of CO2 divided by molar mass of CO2 But substitute mass of CO2 should be substituted in grams. SO u have to convert it.

  2. anonymous
    • one year ago
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    I have used this but my answer is 64.39 psig but the correct answer should be 51.3 psig :( @Rushwr

  3. Rushwr
    • one year ago
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    oh wait here the unit we have to use is psig right? ah then we have to convert the temperature to kelvin and Volume to cubic meters only !

  4. anonymous
    • one year ago
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    i have converted ft3 to L and i have also used 0.0821 L atm/K mol for R

  5. anonymous
    • one year ago
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    |dw:1441548682633:dw|

  6. anonymous
    • one year ago
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    P = 4.53 atm (14.22 psig/1atm) = 64.42 psig

  7. anonymous
    • one year ago
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    does my solution seem right? :(

  8. Rushwr
    • one year ago
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    1lb = 453.592g SO \[n = \frac{ 10 * 453.592g }{ 44gmol ^{-1} } = 103.1mol\] \[R = 8.314 JK ^{-1}mol ^{-1}\] T = 273 +30 = 303K 1ft^3 = 0.028 m^3 So V= 20 * 0.028m^3 = 0.56m^3

  9. Rushwr
    • one year ago
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    then convert it and see !

  10. anonymous
    • one year ago
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    P = 463792.04 ?

  11. anonymous
    • one year ago
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    @Rushwr

  12. Rushwr
    • one year ago
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    That's what I got too I think that's wrong again ! COnvert and see ! I'll check more !

  13. anonymous
    • one year ago
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    what unit is P ? atm?

  14. Rushwr
    • one year ago
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    nop Nm^-2

  15. anonymous
    • one year ago
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    it's 67.27 psig?

  16. Rushwr
    • one year ago
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    Yeah that's what I got too !!!!!!!!! Wondering !

  17. anonymous
    • one year ago
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    hmm maybe my professor got it wrong i don't know ¯\_(ツ)_/¯ :)). I'll just ask him. Thank you so much for helping me :D

  18. Rushwr
    • one year ago
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    Anytym : 0

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