## anonymous one year ago an ethernet cable is 4 m long and has a mass of 0.2 kg . a transverse wave is produced by plucking one end of the taut cable. the pulse makes 4 trips down and back along the cable in 0.8 sec , what is the tension in the cable?

1. anonymous

Let "$$T$$" be the tension in the cable, and then the vertical component of the cable tension is: $$F_v = T×Sin(30)$$ Now, try to solve it using the formula.. @YamadaTasnim

2. anonymous

$trips / time= (1/2L) \sqrt{T/(kg/m)}$ i use this formula.. got it right! @Persia

3. Michele_Laino

the emitted frequency $$\large \nu$$ by the cable is given by the subsequent formula: $\Large \nu = \frac{1}{{2L}}\sqrt {\frac{T}{\rho }} \;\left( {{\text{Hz}}} \right)$ where $$\large \rho$$ is the linear density of the cable, and $$\large T$$ is the tension which is acting on the cable