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anonymous
 one year ago
I am getting the wrong answers and I don't know where I am going wrong! Please help!
4. The line with the equation 5x+y=20 meets the x axis at A and the line with the equation x+2y=22 meets the y axis at B. The two lines intersect at point C.
(iv) Find the coordinates of the point E such that ABEC is a parallelogram.
This is what I have done (I don't know if this is right or not):
I have found the gradient of BA ( 11/4) which I know will be parallel to EC. I then use the point (0,11) to find the equation of the line BA. I get 4y+11x=44 from this.
I do the same for CA (parallel to EB) .
anonymous
 one year ago
I am getting the wrong answers and I don't know where I am going wrong! Please help! 4. The line with the equation 5x+y=20 meets the x axis at A and the line with the equation x+2y=22 meets the y axis at B. The two lines intersect at point C. (iv) Find the coordinates of the point E such that ABEC is a parallelogram. This is what I have done (I don't know if this is right or not): I have found the gradient of BA ( 11/4) which I know will be parallel to EC. I then use the point (0,11) to find the equation of the line BA. I get 4y+11x=44 from this. I do the same for CA (parallel to EB) .

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It wouldnt let me type any more so heres the rest

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I get 5 for the gradient and use point C (2,10) to get the equation of the line 5x+y=20

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I solve the two equations simultaneously to find where they intersect and only get through the first part till I get 9x=56 which I already know is wrong since x has to equal 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I can post a picture of everything too

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1The first line: 5x +y =20 (1), A on this line and A (4,0) The second line : x+2y = 22 (2) , B on this line and B (0,11) Ok??

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1now, if it forms a parallelogram, then the left side is dw:1441547541029:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh wait i think you have A and B wrong.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Show me my mistake, please.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is the answer for the first question it asked saying what the graph looks like

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So B is on the line on the bottom and is is on the line to the left

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1yes, just estimate. As long as my logic is Ok, I am ok.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1agree with me for this?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441547741256:dw That is I need a line parallel to 5x+y =20 and passes through B, right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Now, calculate that line by plugging B coordinate in the equation, I get \(5\color{red}{x}+\color{blue}{y}=20\\5\color{red}{0}+\color{blue}{11}=11\), Hence my new line has the equation 5x +y =11dw:1441547933249:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Same as the line parallel to BC which passes through A (4,0)dw:1441547992236:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1I have this new line is calculated by \(\color{red}{x}+2\color{blue}{y}=22\\\color{red}{4}+2\color{blue}{0}=4\) hence my brand new line is x +2y =4dw:1441548113103:dw

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1So far, I have 2 new lines. Those are 5x+y = 11 and x + 2y =4 Intersection of them is E(2,1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Um no I dont think thats right... the book says the answer is (2,21)

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Whatever the book says, I have a proof of it. https://www.desmos.com/calculator/vku2dwjf3q

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1If the point is 2,21) it can't be form a parallelogram with ABE https://www.desmos.com/calculator/jcjmy55zfm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One thing though is that the Book is saying the quadrilateral is ABEC but on the quadrilateral you have shown me A and B don't connect

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1How can they connect? A is intersection point of the first line with the x axis B is intersection point of the second line with the y axis The two line intersects at C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The other thing is, I actually got (2,1) the first time I tried it, but thought it was wrong since he book said so.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I will send a picture of the graph I made

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The slightly shaded in area is what I assumed some of the parallelogram would be

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry, its not the neatest graph in the world

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Yes, that is the x coordinate of E cannot be negative and y coordinate cannot be exceed 11, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah no? dw:1441548896467:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441548990858:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And then E would complete it. I know you are saying thats not right, can you explain why?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Ok, another proof for this, you have B (0,11) , C (2,10), distance BC is \(BC =\sqrt{(x_Cx_B)^2 +(y_c y_B)^2}=\sqrt 5\) if A (4,0), E(2,21) \(AE=\sqrt{477}\) how can they form a parallelogram?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1That's all I know, if it is wrong still. I am sorry for wasting your time. I am done.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm no that makes sense.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK, thank you very much for your help! You didnt waste my time, actually I am sorry for taking so much of yours

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I hope you have a nice day, for me its back to maths!
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