star_girl
  • star_girl
Please help!!
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
star_girl
  • star_girl
What mass of sulphur trioxide is formed from 96g off sulphur dioxide?
star_girl
  • star_girl
\[2SO _{2} + O _{2} \rightarrow 2SO _{3}\]
star_girl
  • star_girl
@iambatman @iknowplaces13

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Rushwr
  • Rushwr
Hey, According to the stoichiometric ratio we can see the no of moles of SO2 used is equal to the no. of moles of SO3 cuz they both have the same stoichiometric number ! 1) Find the no. of moles of SO2 \[n= \frac{ m }{ M}\] n= no. of moles m= mass of SO2 M= Molar mass of SO2 2) No. of moles of SO2 = no. of moles of SO3 So use the same equation \[n = \frac{ m }{ M }\] Here we know no. of moles and the molar mass so we have to find 'm' So Substitute the values and get the answer !
Rushwr
  • Rushwr
Did you get it ?
Rushwr
  • Rushwr
What was the answer u got ?
star_girl
  • star_girl
I think I get it @Rushwr I got 120g for SO3
Rushwr
  • Rushwr
Yep !

Looking for something else?

Not the answer you are looking for? Search for more explanations.