## anonymous one year ago check my work

1. anonymous

Find the work done in moving a particle once round the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$, z=0 under the field of force given by $\vec F=(2x-y+z)\hat i+(x+y-z^2)\hat j+(3x-2y+4z)\hat k$ z=0 so we have $\vec F=(2x-y)\hat i+(x+y)\hat j+(3x-2y)\hat k$ Parametric equation of the ellipse, $x=5\cos(\theta)$$y=4\sin(\theta)$ $z=0$ $\therefore dx=-5\sin(\theta)d\theta, dy=4\cos(\theta)d\theta, dz=0$ $\therefore d\vec r=dx \hat i+dy \hat j +dz \hat k=-5\sin(\theta)d\theta \hat i+4\cos(\theta)d\theta \hat j$ $\vec F.d \vec r=(2x-y)dx+(x+y)dy=2xdx-ydx+xdy+ydy$ $\vec F. d \vec r=-25\sin(2\theta)d\theta+20\sin^2(\theta)d\theta+20\cos^2(\theta)d\theta+8\sin(2\theta)d\theta$$\vec F.d \vec r=(20-16\sin(2\theta))d\theta$ For an ellipse $0\le \theta \le 2\pi$ therefore $W=\int\limits_{C}(\vec F . d \vec r)=\int\limits_{0}^{2\pi}(20-16\sin(2\theta))d\theta$ $W=[20\theta+8\cos(2\theta)]_{0}^{2\pi}=[(40\pi+8)-(0+8)]=40\pi+8-8=40\pi$

2. anonymous

sorry should be $\oint_{C} (\vec F . d \vec r)=\oint_{0}^{2\pi}(20-16\sin(2\theta)d\theta$ Since ellipse is a closed curve :)

3. amistre64

doesnt work require displacement? if you end up where you started ... my physics is rusty.

4. anonymous

Hmmm that's true but since there's a field present it will affect the particle's motion as it moves around the ellipse, kinda like how a car moves around an elliptical road, friction present at every point will cause it to do some work. I think that is one way to think about it

5. anonymous

Also I think this field is non-conservative $\vec \nabla \times \vec F \neq \vec 0$ So taking a particle to some point and bringing it back in the form of an elliptical path will create a difference in going to the point and return trip

6. amistre64

2x dx 2 (5cos) (-5sin) .... -25 (2 sin cos), which is simplified to a half angle ... it seems to me that all your substitutions are valid.

7. anonymous

@amistre64 thx!!

8. amistre64

9. amistre64

the pun is nice to: 'check my work' and its a problem that involves finding the work done :)

10. anonymous

Oh, I didn't see that!! I guess that deserves 2 medals, 1 for maths and 1 for english!! :P