a jet plane traveling at 550 mph overtakes a propeller plane traveling at 200 mph that had a 4-hour head start. How far from the starting point are the planes?

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a jet plane traveling at 550 mph overtakes a propeller plane traveling at 200 mph that had a 4-hour head start. How far from the starting point are the planes?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Use algebra with the fact the Distance (d) = Rate (r) times time (t) and further you do know that the distance traveled by each plane was equal at the point where jet overtook the prop plane.
Let t = time of Jet plane flight at the point of overtake. Let t + 4 = time of prop plane flight (from start to overtake point) The distance for each plane is equal, and furthermore we know that d=rt. Step 1. calculate distance of Jet plane. d=rt, so d=550 t Step 2. calculate distance of prop pland d=rt, so d=200(t + 4) = 200t + 800 Since the distances are equal, Step 3. Set up the equation: 550t = 200t + 800 Now solve for t and calculate the distance which is the answer that is being sought. d=rt Use the Jets rate and time. and then verify by solving for distance of the prop (using t + 4) Both distances should be equal verifying the correctness of your answer.

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