Helpjebal
  • Helpjebal
f(x) = 5 / (x - 2) answer: x ≠ 2 My lesson does not tell me how they got that answer. I can not figure it out.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What do you think is the value of f(x) when x=2, or in short, what is f(2)?
Helpjebal
  • Helpjebal
if x = 2 then it would be f(x)= 5/0 which is just f(x) = 5?
anonymous
  • anonymous
Nope, division by 0 is not defined so \[\frac{5}{0}\] has no meaning, that's why x can take any value except 2 This is also the reason why you can't multiply both sides of an equation by 0 consider \[y=2x\] If you multiply both sides by 0 you get \[y \times 0=2x \times 0\] Now one may say to get back the original equation we simply have to divide by 0 \[\frac{y \times 0}{0}=\frac{2x \times 0}{0}\] Now division by 0 is not defined, so this has no meaning, so you just simply can't multiply both sides of an equation by 0

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Also remember \[\frac{5}{1}=5\] and you are saying \[\frac{5}{0}=5\] This implies that \[1=0\] which is not true
Helpjebal
  • Helpjebal
okay so since division by 0 is not defined, it would give x an infinite amount of values other than 2 because of how we worked out the equation? like x - 2 = 0 turns into x = 2 and when x is replaced by 2 we get 0 which brings us back to it being undefined?
anonymous
  • anonymous
Yes and this is what we call the "domain" of the function, the set of all the values that x can take symbolically we write |dw:1441558284235:dw| Set of real numbers minus the set containing number 2
anonymous
  • anonymous
Basically x can take any value except 2 because for 2 it is not defined
Helpjebal
  • Helpjebal
thank you!!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.