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The answer is 10000 N

|dw:1441558783042:dw|First job is to determine the normal force, \(F_N\). Can you do that?

@ospreytriple yes, it is 39200 N

Sorry. **\(F_{g,y'}\)

\[F _{g*y}\] + 37864.3 N

not +... *equals

@ospreytriple Here is what I did:|dw:1441560405546:dw|

I'm so confused... I don't really get it.

|dw:1441619539725:dw|

Yes, friction force <= mu Normal force

@IrishBoy123 |dw:1441648009736:dw|

You're welcome! Glad that it is resolved.
:)