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happykiddo

  • one year ago

URGENT HELP:::A car accelerates at a constant rate from zero to 48.9 m/s in 10 seconds and then slows to 13.1 m/s in 5 seconds. What is its average acceleration to the nearest tenth of a m/s2 during the 15 seconds? The answer is 0.9, WHY?

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  1. happykiddo
    • one year ago
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    I used the formula \[Average Acceleration= \Delta V / \Delta t\]

  2. IrishBoy123
    • one year ago
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    for the whole journey what are \[\Delta V\] \[\Delta t\]

  3. IrishBoy123
    • one year ago
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    *whole* journey

  4. happykiddo
    • one year ago
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    delta V= 13.1m/s - 48.9 m/s delta t= 5 s- 10s

  5. IrishBoy123
    • one year ago
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    "at a constant rate from zero"

  6. IrishBoy123
    • one year ago
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    "at a constant rate **from zero**"

  7. IrishBoy123
    • one year ago
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    the journey started at t = 0

  8. happykiddo
    • one year ago
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    So are you saying to just use 15 seconds as my "t" value?

  9. IrishBoy123
    • one year ago
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    yes!

  10. IrishBoy123
    • one year ago
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    so does the question :p "What is its average acceleration to the nearest tenth of a m/s2 **during the 15 seconds**"

  11. happykiddo
    • one year ago
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    I've already tried that it gives me -2.4.....not 0.9

  12. IrishBoy123
    • one year ago
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    what speed did the journey start at? what speed did the journey end at?

  13. happykiddo
    • one year ago
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    Alright I got the answer :P , feeling pretty stupid that i used 48.9 m/s as my initial velocity. I appreciate the help. Thanks : )

  14. IrishBoy123
    • one year ago
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    good job! been there, done that myself :-)

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