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  • one year ago

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  1. anonymous
    • one year ago
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    |dw:1441562392048:dw| How can I find the equation of this curve?It's a quadrant of a circle with intercept a

  2. freckles
    • one year ago
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    and it looks like the center is (0,0) so equation of the circle would be x^2+y^2=a^2 where a is the radius

  3. anonymous
    • one year ago
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    |dw:1441562610601:dw|

  4. freckles
    • one year ago
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    lol yes :p

  5. anonymous
    • one year ago
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    Yes I know, but I want an equation that is just for this piece of quadrant and not for entire circle

  6. freckles
    • one year ago
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    well you can say x^2+y^2=a^2 where x>0 and y>0

  7. anonymous
    • one year ago
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    for example for a semicircle lying in the upper half we can write \[y=\sqrt{a^2-x^2}\] Can't we do something similar for a quadrant?

  8. freckles
    • one year ago
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    or you can solve for y y^2=a^2-x^2 y=sqrt(a^2-x^2) is the top part of the circle so you can say y=sqrt(a^2-x^2) where x>0

  9. freckles
    • one year ago
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    nope that is all I got you can do half of a circle or full circle and then make restrictions on the circle or half circle

  10. anonymous
    • one year ago
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    ok thank you

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