## anonymous one year ago ques

1. anonymous

|dw:1441562392048:dw| How can I find the equation of this curve?It's a quadrant of a circle with intercept a

2. freckles

and it looks like the center is (0,0) so equation of the circle would be x^2+y^2=a^2 where a is the radius

3. anonymous

|dw:1441562610601:dw|

4. freckles

lol yes :p

5. anonymous

Yes I know, but I want an equation that is just for this piece of quadrant and not for entire circle

6. freckles

well you can say x^2+y^2=a^2 where x>0 and y>0

7. anonymous

for example for a semicircle lying in the upper half we can write $y=\sqrt{a^2-x^2}$ Can't we do something similar for a quadrant?

8. freckles

or you can solve for y y^2=a^2-x^2 y=sqrt(a^2-x^2) is the top part of the circle so you can say y=sqrt(a^2-x^2) where x>0

9. freckles

nope that is all I got you can do half of a circle or full circle and then make restrictions on the circle or half circle

10. anonymous

ok thank you