anonymous
  • anonymous
I really need help with this question
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
I need to simplify this expression rewrite it in radical form
anonymous
  • anonymous
anyone please

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EmmaTassone
  • EmmaTassone
you should do that with the following properties: \[\sqrt[n]{a}=a^{\frac{ 1 }{ n }}\] \[a ^{n}.b ^{m}= a ^{n+m}\]
EmmaTassone
  • EmmaTassone
using those you can rewrite the expression as you want
EmmaTassone
  • EmmaTassone
and a,b,m,n are all real numbers
anonymous
  • anonymous
alright so would I get 1/2c[^{3/5}\] x -18/4d[^{1/6}\]
EmmaTassone
  • EmmaTassone
mm.. i would appreciate you to write your result with maths symbols because i didint understand what to got to.
anonymous
  • anonymous
1/2c^3/5 x -18/4 D ^1/6
EmmaTassone
  • EmmaTassone
where the x comes from?
anonymous
  • anonymous
multiplication symbol I will use a different one next time
EmmaTassone
  • EmmaTassone
what happened with the c factor?
EmmaTassone
  • EmmaTassone
try first to multiply all the fraction, so you will have them in only one fraction
EmmaTassone
  • EmmaTassone
and you wont have to care about them anymore
EmmaTassone
  • EmmaTassone
Example: \[\frac{ 1 }{3 }a ^{-5}.\frac{ 1 }{ 3 }b ^{\frac{ 4 }{ 3 }}.\frac{ 1 }{ 2 }\sqrt[3]{b}=\frac{ 1 }{ 18 }(a ^{-5}.b ^{\frac{ 4 }{ 3 }}.\sqrt[3]{b})\]
EmmaTassone
  • EmmaTassone
and then you use the properties i gave you @sethgprescott : \[\frac{ 1 }{ 18 }.(a ^{-5}.b ^{\frac{ 4 }{ 3 }}.b^ \frac{ 1 }{ 3 })=\frac{ 1 }{ 18 }(a^{-5}.b^{\frac{ 4 }{ 3 }+\frac{ 1 }{ 3 }})\]

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