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anonymous

  • one year ago

I really need help with this question

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I need to simplify this expression rewrite it in radical form

  3. anonymous
    • one year ago
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    anyone please

  4. EmmaTassone
    • one year ago
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    you should do that with the following properties: \[\sqrt[n]{a}=a^{\frac{ 1 }{ n }}\] \[a ^{n}.b ^{m}= a ^{n+m}\]

  5. EmmaTassone
    • one year ago
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    using those you can rewrite the expression as you want

  6. EmmaTassone
    • one year ago
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    and a,b,m,n are all real numbers

  7. anonymous
    • one year ago
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    alright so would I get 1/2c[^{3/5}\] x -18/4d[^{1/6}\]

  8. EmmaTassone
    • one year ago
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    mm.. i would appreciate you to write your result with maths symbols because i didint understand what to got to.

  9. anonymous
    • one year ago
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    1/2c^3/5 x -18/4 D ^1/6

  10. EmmaTassone
    • one year ago
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    where the x comes from?

  11. anonymous
    • one year ago
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    multiplication symbol I will use a different one next time

  12. EmmaTassone
    • one year ago
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    what happened with the c factor?

  13. EmmaTassone
    • one year ago
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    try first to multiply all the fraction, so you will have them in only one fraction

  14. EmmaTassone
    • one year ago
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    and you wont have to care about them anymore

  15. EmmaTassone
    • one year ago
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    Example: \[\frac{ 1 }{3 }a ^{-5}.\frac{ 1 }{ 3 }b ^{\frac{ 4 }{ 3 }}.\frac{ 1 }{ 2 }\sqrt[3]{b}=\frac{ 1 }{ 18 }(a ^{-5}.b ^{\frac{ 4 }{ 3 }}.\sqrt[3]{b})\]

  16. EmmaTassone
    • one year ago
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    and then you use the properties i gave you @sethgprescott : \[\frac{ 1 }{ 18 }.(a ^{-5}.b ^{\frac{ 4 }{ 3 }}.b^ \frac{ 1 }{ 3 })=\frac{ 1 }{ 18 }(a^{-5}.b^{\frac{ 4 }{ 3 }+\frac{ 1 }{ 3 }})\]

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spraguer (Moderator)
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