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happykiddo
 one year ago
A speeder traveling at 42 m/s passes a motorcycle policeman at rest at the side of the road. The policeman accelerates at 3.66 m/s2. To the nearest tenth of a second how long does it take the policeman to catch the speeder? Both located at the same place and time.
happykiddo
 one year ago
A speeder traveling at 42 m/s passes a motorcycle policeman at rest at the side of the road. The policeman accelerates at 3.66 m/s2. To the nearest tenth of a second how long does it take the policeman to catch the speeder? Both located at the same place and time.

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happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1I used the formula \[S=1/2(a)(t)^2+ Vi(t)+Si\]

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1Because of the same place and time I made cop=speeder

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1So the way I did it is (1/2)(3.66m/s^2)(t^2)=(42m/s)(t)

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1I got it!! I incorrectly punched some numbers into the calculator before. But thank you for your effort : )

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The speeder is traveling at constant velocity The policeman is traveling at constant acceleration. For constant velocity I would use \[d=vt\] and for constant acceleration, I would use \[final distance=initial distance+vt+\frac{ 1 }{ 2 }at^2\] Well, what do you know? They both equals to distance traveled. So you set them equal to each other by solving for time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0_ lol. Right when I almost finished.

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1But still thanks!! Could you help with another problem?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Writing in the equation sheet usually delays me.

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1I'l lpost it as a new question.

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1A car traveling at 16 m/s accelerates at 3.95 m/s2 for 6 seconds. To the nearest meter how far does it travel? I used the same equation from the last question but got 77.1 meters instead of 167(correct answer).

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1\[S=\frac{ 1 }{ 2 }(a)(t)^2+Vi(t)+Si\]

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1a=3.95 t=6 Vi=0 Si=0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, the initial velocity is 16m/s. It does not say the vehicle started from rest.

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1Gotcha, let me try it out.

happykiddo
 one year ago
Best ResponseYou've already chosen the best response.1I got it! Thank you for the help.
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