A mathematician states that her children’s ages are all prime numbers that multiply together to give 7,429. She also says that two of her children are teenagers. What are her children s age?

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A mathematician states that her children’s ages are all prime numbers that multiply together to give 7,429. She also says that two of her children are teenagers. What are her children s age?

Mathematics
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so we have \[a \cdot b \cdot c=7429\]
we know prime numbers are odd for the most part
and we know 7429 is not even so none of the primes are 2

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two of her children are teenagers so they could be 13,17, or 19
I would probably try to write the prime factorization of 7429
can you do that?
wait what are prime numbers? :$
prime numbers are integers that are only divisible by themselves and 1.
the key here is just to write 7429 in prime factorization that is all there is to the problem
like for example 25=5*5 or 5^2 31 is prime 25 was not umm... 2 is the only even prime
I dont even know what factorization means >.< I missed few days of school.
one tip... given the last digit is 9... I'd divide the original number by 17
example: the prime factorization of 12=2*2*3
thanks <3
then see if the other 2 primes in the teens divides evenly
I don't know , I will try to figure it out thanks though
well the key to help was the teenager part
yeah , teens
"so they could be 13,17, or 19" exactly two of these numbers will be factors
then you have to find the other factor by divide 7429 by the product of two teenagers
what is 7429 divided by 13 ?
2476.3
you should get some kind of remainder that isn't 0 which would mean 13 is not factor of 7429 which means the other two number 17 and 19 are factors of 7429
so you only have to find one last factor
\[\frac{7429}{17 \cdot 19}=?\]
So far I have done , 17/7429 = 437 /23 = 19
that leaves me with 1 , if i divide it within 19 itself
is this what you meant to say: \[\frac{7429}{17 \cdot 19}=\frac{7429}{323}=23\]
which means 17*19*23=7429
kinda
oh I think I get what you are saying but those fractions aren't equal
\[\frac{7429}{17}=437 \\ \frac{437}{23}=19\]
first fraction gives 7429=17(437) then second fraction says 437=23(19)
so replace 437 in 7429=17(437) with 23(19) so 7429=17(23*19)
and you did it girl good job!
Oh my gosh thank you so much <3
and 17,19,23 are all prime because they are only divisible by themselves or 1
Can I get this straight first XD I wanna be completely sure 17/7421 = 19 divide by 23 or what? Oh my gosh I am confusing myself

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