happykiddo
  • happykiddo
If the particle’s position on the x-axis is now given by the function x=(1t^2+1t+-2)m, where t is in s. To the nearest 0.1 m, what is the turning point (where the particle reverses direction of motion) of the particle's position?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
happykiddo
  • happykiddo
Could someone explain to me what a "turning point" is in relation to this problem?
happykiddo
  • happykiddo
The answer is 5, if that helps any.
EmmaTassone
  • EmmaTassone
the function is:\[x(t)=t ^{2}+t-2\] right?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

happykiddo
  • happykiddo
So sorry the actual function is x=(-2t^2+0t+5) not the one stated above.
happykiddo
  • happykiddo
not the one in the question above. Function different overall question the same.
happykiddo
  • happykiddo
sorry for the confusion.
EmmaTassone
  • EmmaTassone
the turning point is a point at which the derivative changes sign
EmmaTassone
  • EmmaTassone
so you should derivate the function and see when the derivative becomes zero. And when you find that turning point then you will have to evaluate in your position function to know at what position was the particle when it reverse his direction of motion.
happykiddo
  • happykiddo
I understand what I must do now. Thank you very much! : )
EmmaTassone
  • EmmaTassone
no problem

Looking for something else?

Not the answer you are looking for? Search for more explanations.