plz i need help :( Evaluate the expression if a = 1 and b = 2. fraction numerator 5 left parenthesis a star times plus 3 b right parenthesis over denominator a b end fraction A. 20 B. 5.5 C. 15 D. 17.5

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plz i need help :( Evaluate the expression if a = 1 and b = 2. fraction numerator 5 left parenthesis a star times plus 3 b right parenthesis over denominator a b end fraction A. 20 B. 5.5 C. 15 D. 17.5

Algebra
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\[\frac{5( \star \cdot 3b)}{ab}\] any idea what the value we should plug in for the star ?
1
so you are given \[a=1, b=2, \star=1\]

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replace a with 1 replace b with 2 replace star with 1 then \[\frac{5( \star \cdot 3b)}{ab}=\frac{5(1 \cdot 3(2))}{1(2)}\]
no the star is a
oh your problem said something about a star in it
and a is 1
sorry about that
I'm sorry kind of confused about times plus and what that means exactly
can you draw the problem or is it really worded like that?
ok
|dw:1441573677006:dw|
\[\frac{5(a+3b)}{ab} \\ \\ \text{ okay so replace } a \text{ with 1} \text{ and } b \text{ with 2} \\ \frac{5(1+3 \cdot 2)}{1(2)}\]
do you know how to do 5(1+3*2) and 1(2)?
no
1(2)? come on you know this 2
1 times a is a
1 times 2 is 2
ok
5(1+3*2) here we apply order of operations what is 3*2?
6
ok so we have now 5(1+6)
1+6=?
7
and then whatever you get for 1+6 multiply that result by 5 so you should end up with 5 times 7
which is..
35
\[\frac{5(a+3b)}{ab} \\ \\ \text{ okay so replace } a \text{ with 1} \text{ and } b \text{ with 2} \\ \frac{5(1+3 \cdot 2)}{1(2)} \\ =\frac{5(1+6)}{2}=\frac{5(7)}{2}=\frac{35}{2}\]
and you are basically done just need to write as a decimal
since your choices are written that way
but there's no 35/2
yes that is why I said to write as a decimal
35.2
how did you get 35.2?
|dw:1441574329519:dw| 2 doesn't go into 3, 3 times... 2 goes into 3, 1 times
|dw:1441574353259:dw|
2 goes into 15 how many times?
oh
7
|dw:1441574417155:dw| and finally 2 goes into 10 how many times?
5
right |dw:1441574443279:dw| \[\frac{35}{2}=17.5\]
thx

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