anonymous
  • anonymous
.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1441573642078:dw|
anonymous
  • anonymous
@freckles
iwillrektyou
  • iwillrektyou
n this case, you need the distance formula.

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iwillrektyou
  • iwillrektyou
Those are ordered pairs, right? That show where each point is located?
anonymous
  • anonymous
ya
iwillrektyou
  • iwillrektyou
Do you know the distance formula?
anonymous
  • anonymous
sqrt of x2-x1 ^2+ y2-y2^2 pronounced y-1, not y ^2
iwillrektyou
  • iwillrektyou
Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6).
iwillrektyou
  • iwillrektyou
Just substitute and solve. Let me know if you need help.
anonymous
  • anonymous
64+169
anonymous
  • anonymous
want me to continue or something???
iwillrektyou
  • iwillrektyou
Yes. I will check your answers as you go, if you would like.
anonymous
  • anonymous
233 now what???
iwillrektyou
  • iwillrektyou
You have to do the same thing with the points (-2, 7) and (-5, 3)
anonymous
  • anonymous
81+64 145
iwillrektyou
  • iwillrektyou
In order to find the width. Then, you just multiply the 2. I will be checking your work,
anonymous
  • anonymous
what do i do in order to find the width??
iwillrektyou
  • iwillrektyou
To find the width, use the distance formula for these 2 points: (-2, 7) and (-5, 3)
anonymous
  • anonymous
yah wchich is 145
iwillrektyou
  • iwillrektyou
Yes. To find the area, just multiply the length and width together.
anonymous
  • anonymous
um that's 33785 AAAANNNNDDD thats not an answer choice you are wrong
iwillrektyou
  • iwillrektyou
I am checking your work, and a step was done wrong.
iwillrektyou
  • iwillrektyou
For the width, it is 5.
iwillrektyou
  • iwillrektyou
And I am double checking my work for the length,
anonymous
  • anonymous
how do you get 5??????
iwillrektyou
  • iwillrektyou
Ok so, Sqrt (-5 + 2)^2 + (3 - 7)^2 --> Sqrt (-3)^2 + (-4)^2 --> Sqrt (9 + 16) --> 5
anonymous
  • anonymous
okay okaywhats the lenght
iwillrektyou
  • iwillrektyou
15
iwillrektyou
  • iwillrektyou
But do you understand the concept?
freckles
  • freckles
"Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6). " \[\text{ distance between these two points is } \\ \sqrt{(-5-7)^2+(3-(-6))^2} \\ =\sqrt{(-5-7)^2+(3+6)^2} \\ =\sqrt{(-12)^2+(9)^2} .. \text{ so on ... }\]
anonymous
  • anonymous
yeah so 75
iwillrektyou
  • iwillrektyou
Yes. 75 is correct.
anonymous
  • anonymous
can you help with one more?
iwillrektyou
  • iwillrektyou
I will try, but I am not very good at geometry, as I just started learning it. But shoot.
anonymous
  • anonymous
|dw:1441574726192:dw| find the perimeter
anonymous
  • anonymous
no i dont think so i think this has to do with the distance formula
iwillrektyou
  • iwillrektyou
Hmm..... I am not sure how to do this. Do they provide you with an ordered pair that substitutes for the variables?
anonymous
  • anonymous
nope @freckles do you have any idea?
freckles
  • freckles
|dw:1441574975096:dw| the bottom we don't really have to use the distance formula for you know the distance from a to 0 is a and the distance from -a to 0 is a so the bottom length is just a+a=2a
freckles
  • freckles
|dw:1441575013692:dw| we have to use the distance formula for the other two sides though
anonymous
  • anonymous
okay
anonymous
  • anonymous
thank you guys so much for helping btw so what do we do now???
iwillrektyou
  • iwillrektyou
Sorry I couldn't help. I'm only in 8th grade. :(
anonymous
  • anonymous
im in 8th too
iwillrektyou
  • iwillrektyou
Cool. Hopefully freckles will be able to help you do this,
freckles
  • freckles
distance formula for (-a,c) to (0,b) since that would be the length of that one side distance formula for (a,c) to (0,b) since that would be the length for that last side then just add all the lengths up to find the perimeter value
anonymous
  • anonymous
can you help me in doing that?
freckles
  • freckles
what do you need help with exactly? entering in the values in to the formula?
anonymous
  • anonymous
yeah just enter and then i'll solve
freckles
  • freckles
I will do one the distance from (-a,c) to (0,b) is: \[\sqrt{(-a-0)^2+(c-b)^2} \\ \sqrt{(-a)^2+(c-b)^2} \\ \sqrt{a^2+(c-b)^2}\] you try finding the distance from (a,c) to (0,b) now..
anonymous
  • anonymous
so would it be sqrt (a+a)^2+(c-c)^2?
freckles
  • freckles
are you using the points (a,c) and (0,b)?
freckles
  • freckles
the change of x is a-0 not a+a the change of y is c-b not c-c
anonymous
  • anonymous
so sqrt (a-o)^2+(c-b)^2?
freckles
  • freckles
yes and a-0 is just a
freckles
  • freckles
|dw:1441575476337:dw| \[\text{ so the distance between } (-a,c) \text{ and } (a,c) \text{ is } 2a \\ \text{ and the distance between } (a,c) \text{ and } (0,b) \text{ is } \sqrt{a^2+(c-b)^2} \\ \text{ and the distance between } (-a,c) \text{ and } (0,b) \text{ is } \sqrt{a^2+(c-b)^2}\] now just add up all 3 distances to find the perimeter
anonymous
  • anonymous
so 2 sqrt (a^2+ (c-b)^2 +2a
freckles
  • freckles
yes: \[2a+2 \sqrt{a^2+(c-b)^2}\]
anonymous
  • anonymous
thats not an answer choice
anonymous
  • anonymous
the answer choices are 2a sqrt a^2-(c-b)^2 or 2a sqrt a^2+(c+b)^2
freckles
  • freckles
\[2a+2 \sqrt{a^2+(c-b)^2} \\ \text{ is the same as } 2a+2 \sqrt{a^2+(b-c)^2} \\ \text{ which is the same as } 2a+2\sqrt{(b-c)^2+a^2} \\ \text{ this is the same as } 2\sqrt{(b-c)^2+a^2}+2a \\ \text{ there is a lot of other ways \to express this }\]
freckles
  • freckles
you can also factor out the 2... \[2(\sqrt{(b-c)^2+a^2}+a)\]
anonymous
  • anonymous
but thats not even a choice
freckles
  • freckles
it is probably a choice but it is just written a bit different as I said there is a few different ways to express that same answer
anonymous
  • anonymous
|dw:1441575733104:dw| these are my choices
freckles
  • freckles
can't really read that
anonymous
  • anonymous
|dw:1441575827490:dw|
anonymous
  • anonymous
that second one should be a plus 2a
freckles
  • freckles
yeah those answers are totally wrong I don't why they put the square root over everything like that
anonymous
  • anonymous
it shouldn't be over the 2a sorry my bad
freckles
  • freckles
you do know when you asked me is this the answer I said yes... you wrote so 2 sqrt (a^2+ (c-b)^2 +2a and then I said "yes \[2a+2 \sqrt{a^2+(c-b)^2}\]" and I said yes assuming you meant to write a ) at the end of the (c-b)^2 there that is 2sqrt(a^2+(c-b)^2)+2a
freckles
  • freckles
addition is commutative 3+2 is the same as 2+3
freckles
  • freckles
\[2a+2 \sqrt{a^2+(c-b)^2} \text{ is the same as } 2 \sqrt{a^2+(c-b)^2}+2a\]
anonymous
  • anonymous
sorry its late a night im really tire
anonymous
  • anonymous
yah but thats still not an answer?
anonymous
  • anonymous
im not talking about the 2a or the 2, look inside the sqrt. the answer has it as a^2-(c-b)^2 or a^2+(c+b)^2
freckles
  • freckles
both of those are wrong though
anonymous
  • anonymous
well that's what they have as an answer....
freckles
  • freckles
well I don't know what you want me to tell you
freckles
  • freckles
recall the distance formula is: \[\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]
freckles
  • freckles
do you see there is a plus between the two square parts?
freckles
  • freckles
and there is a minus in between the things inside the ( )
anonymous
  • anonymous
yeah i get it that you are right i just don't know which one to pick
freckles
  • freckles
the ordered pairs were definitely (0,b) and (a,c) and (-a,c) right?
anonymous
  • anonymous
yup
freckles
  • freckles
the only thing I can do is guess which one they meant as the right answer but either guess I make is going to be wrong whether it is marked right or not
anonymous
  • anonymous
should i go with the plus or the minus?
freckles
  • freckles
let me confirm these are the choices: \[2a+2 \sqrt{a^2-(c-b)^2} \\ 2a+2 \sqrt{a^2+(c+b)^2}\]
freckles
  • freckles
there are no other choices?
freckles
  • freckles
like you can't pick a none of these?
anonymous
  • anonymous
the only other choices are 6a and 9a
freckles
  • freckles
lol I don't know go with the -
freckles
  • freckles
but please tell your teacher that there is a type-o
anonymous
  • anonymous
okay
anonymous
  • anonymous
Anyone else have any ideas?
anonymous
  • anonymous
@freckles i think i know what the answer is

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