- anonymous

.

- chestercat

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- anonymous

|dw:1441573642078:dw|

- anonymous

- iwillrektyou

n this case, you need the distance formula.

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## More answers

- iwillrektyou

Those are ordered pairs, right? That show where each point is located?

- anonymous

ya

- iwillrektyou

Do you know the distance formula?

- anonymous

sqrt of x2-x1 ^2+ y2-y2^2
pronounced y-1, not y ^2

- iwillrektyou

Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6).

- iwillrektyou

Just substitute and solve. Let me know if you need help.

- anonymous

64+169

- anonymous

want me to continue or something???

- iwillrektyou

Yes. I will check your answers as you go, if you would like.

- anonymous

233
now what???

- iwillrektyou

You have to do the same thing with the points (-2, 7) and (-5, 3)

- anonymous

81+64
145

- iwillrektyou

In order to find the width. Then, you just multiply the 2. I will be checking your work,

- anonymous

what do i do in order to find the width??

- iwillrektyou

To find the width, use the distance formula for these 2 points: (-2, 7) and (-5, 3)

- anonymous

yah wchich is 145

- iwillrektyou

Yes. To find the area, just multiply the length and width together.

- anonymous

um that's 33785
AAAANNNNDDD thats not an answer choice you are wrong

- iwillrektyou

I am checking your work, and a step was done wrong.

- iwillrektyou

For the width, it is 5.

- iwillrektyou

And I am double checking my work for the length,

- anonymous

how do you get 5??????

- iwillrektyou

Ok so,
Sqrt (-5 + 2)^2 + (3 - 7)^2 -->
Sqrt (-3)^2 + (-4)^2 -->
Sqrt (9 + 16) -->
5

- anonymous

okay okaywhats the lenght

- iwillrektyou

15

- iwillrektyou

But do you understand the concept?

- freckles

"Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6).
"
\[\text{ distance between these two points is } \\ \sqrt{(-5-7)^2+(3-(-6))^2} \\ =\sqrt{(-5-7)^2+(3+6)^2} \\ =\sqrt{(-12)^2+(9)^2} .. \text{ so on ... }\]

- anonymous

yeah so 75

- iwillrektyou

Yes. 75 is correct.

- anonymous

can you help with one more?

- iwillrektyou

I will try, but I am not very good at geometry, as I just started learning it. But shoot.

- anonymous

|dw:1441574726192:dw|
find the perimeter

- anonymous

no i dont think so i think this has to do with the distance formula

- iwillrektyou

Hmm..... I am not sure how to do this. Do they provide you with an ordered pair that substitutes for the variables?

- anonymous

nope @freckles do you have any idea?

- freckles

|dw:1441574975096:dw|
the bottom we don't really have to use the distance formula for
you know the distance from a to 0 is a
and the distance from -a to 0 is a
so the bottom length is just a+a=2a

- freckles

|dw:1441575013692:dw|
we have to use the distance formula for the other two sides though

- anonymous

okay

- anonymous

thank you guys so much for helping btw
so what do we do now???

- iwillrektyou

Sorry I couldn't help. I'm only in 8th grade. :(

- anonymous

im in 8th too

- iwillrektyou

Cool. Hopefully freckles will be able to help you do this,

- freckles

distance formula for (-a,c) to (0,b)
since that would be the length of that one side
distance formula for (a,c) to (0,b)
since that would be the length for that last side
then just add all the lengths up to find the perimeter value

- anonymous

can you help me in doing that?

- freckles

what do you need help with exactly?
entering in the values in to the formula?

- anonymous

yeah just enter and then i'll solve

- freckles

I will do one
the distance from (-a,c) to (0,b)
is:
\[\sqrt{(-a-0)^2+(c-b)^2} \\ \sqrt{(-a)^2+(c-b)^2} \\ \sqrt{a^2+(c-b)^2}\]
you try finding the distance from (a,c) to (0,b) now..

- anonymous

so would it be sqrt (a+a)^2+(c-c)^2?

- freckles

are you using the points (a,c) and (0,b)?

- freckles

the change of x is a-0 not a+a
the change of y is c-b not c-c

- anonymous

so sqrt (a-o)^2+(c-b)^2?

- freckles

yes and a-0 is just a

- freckles

|dw:1441575476337:dw|
\[\text{ so the distance between } (-a,c) \text{ and } (a,c) \text{ is } 2a \\ \text{ and the distance between } (a,c) \text{ and } (0,b) \text{ is } \sqrt{a^2+(c-b)^2} \\ \text{ and the distance between } (-a,c) \text{ and } (0,b) \text{ is } \sqrt{a^2+(c-b)^2}\]
now just add up all 3 distances to find the perimeter

- anonymous

so 2 sqrt (a^2+ (c-b)^2 +2a

- freckles

yes:
\[2a+2 \sqrt{a^2+(c-b)^2}\]

- anonymous

thats not an answer choice

- anonymous

the answer choices are 2a sqrt a^2-(c-b)^2
or 2a sqrt a^2+(c+b)^2

- freckles

\[2a+2 \sqrt{a^2+(c-b)^2} \\ \text{ is the same as } 2a+2 \sqrt{a^2+(b-c)^2} \\ \text{ which is the same as } 2a+2\sqrt{(b-c)^2+a^2} \\ \text{ this is the same as } 2\sqrt{(b-c)^2+a^2}+2a \\ \text{ there is a lot of other ways \to express this }\]

- freckles

you can also factor out the 2...
\[2(\sqrt{(b-c)^2+a^2}+a)\]

- anonymous

but thats not even a choice

- freckles

it is probably a choice but it is just written a bit different
as I said there is a few different ways to express that same answer

- anonymous

|dw:1441575733104:dw|
these are my choices

- freckles

can't really read that

- anonymous

|dw:1441575827490:dw|

- anonymous

that second one should be a plus 2a

- freckles

yeah those answers are totally wrong
I don't why they put the square root over everything like that

- anonymous

it shouldn't be over the 2a sorry my bad

- freckles

you do know when you asked me is this the answer
I said yes...
you wrote so 2 sqrt (a^2+ (c-b)^2 +2a
and then I said
"yes
\[2a+2 \sqrt{a^2+(c-b)^2}\]"
and I said yes assuming you meant to write a ) at the end of the (c-b)^2 there
that is 2sqrt(a^2+(c-b)^2)+2a

- freckles

addition is commutative
3+2 is the same as 2+3

- freckles

\[2a+2 \sqrt{a^2+(c-b)^2} \text{ is the same as } 2 \sqrt{a^2+(c-b)^2}+2a\]

- anonymous

sorry its late a night im really tire

- anonymous

yah but thats still not an answer?

- anonymous

im not talking about the 2a or the 2, look inside the sqrt. the answer has it as a^2-(c-b)^2 or a^2+(c+b)^2

- freckles

both of those are wrong though

- anonymous

well that's what they have as an answer....

- freckles

well I don't know what you want me to tell you

- freckles

recall the distance formula is:
\[\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]

- freckles

do you see there is a plus between the two square parts?

- freckles

and there is a minus in between the things inside the ( )

- anonymous

yeah i get it that you are right i just don't know which one to pick

- freckles

the ordered pairs were definitely (0,b) and (a,c) and (-a,c) right?

- anonymous

yup

- freckles

the only thing I can do is guess which one they meant as the right answer
but either guess I make is going to be wrong whether it is marked right or not

- anonymous

should i go with the plus or the minus?

- freckles

let me confirm these are the choices:
\[2a+2 \sqrt{a^2-(c-b)^2} \\ 2a+2 \sqrt{a^2+(c+b)^2}\]

- freckles

there are no other choices?

- freckles

like you can't pick a none of these?

- anonymous

the only other choices are 6a and 9a

- freckles

lol I don't know go with the -

- freckles

but please tell your teacher that there is a type-o

- anonymous

okay

- anonymous

Anyone else have any ideas?

- anonymous

@freckles i think i know what the answer is

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