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  1. anonymous
    • one year ago
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    |dw:1441573642078:dw|

  2. anonymous
    • one year ago
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    @freckles

  3. iwillrektyou
    • one year ago
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    n this case, you need the distance formula.

  4. iwillrektyou
    • one year ago
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    Those are ordered pairs, right? That show where each point is located?

  5. anonymous
    • one year ago
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    ya

  6. iwillrektyou
    • one year ago
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    Do you know the distance formula?

  7. anonymous
    • one year ago
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    sqrt of x2-x1 ^2+ y2-y2^2 pronounced y-1, not y ^2

  8. iwillrektyou
    • one year ago
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    Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6).

  9. iwillrektyou
    • one year ago
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    Just substitute and solve. Let me know if you need help.

  10. anonymous
    • one year ago
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    64+169

  11. anonymous
    • one year ago
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    want me to continue or something???

  12. iwillrektyou
    • one year ago
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    Yes. I will check your answers as you go, if you would like.

  13. anonymous
    • one year ago
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    233 now what???

  14. iwillrektyou
    • one year ago
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    You have to do the same thing with the points (-2, 7) and (-5, 3)

  15. anonymous
    • one year ago
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    81+64 145

  16. iwillrektyou
    • one year ago
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    In order to find the width. Then, you just multiply the 2. I will be checking your work,

  17. anonymous
    • one year ago
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    what do i do in order to find the width??

  18. iwillrektyou
    • one year ago
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    To find the width, use the distance formula for these 2 points: (-2, 7) and (-5, 3)

  19. anonymous
    • one year ago
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    yah wchich is 145

  20. iwillrektyou
    • one year ago
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    Yes. To find the area, just multiply the length and width together.

  21. anonymous
    • one year ago
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    um that's 33785 AAAANNNNDDD thats not an answer choice you are wrong

  22. iwillrektyou
    • one year ago
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    I am checking your work, and a step was done wrong.

  23. iwillrektyou
    • one year ago
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    For the width, it is 5.

  24. iwillrektyou
    • one year ago
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    And I am double checking my work for the length,

  25. anonymous
    • one year ago
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    how do you get 5??????

  26. iwillrektyou
    • one year ago
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    Ok so, Sqrt (-5 + 2)^2 + (3 - 7)^2 --> Sqrt (-3)^2 + (-4)^2 --> Sqrt (9 + 16) --> 5

  27. anonymous
    • one year ago
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    okay okaywhats the lenght

  28. iwillrektyou
    • one year ago
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    15

  29. iwillrektyou
    • one year ago
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    But do you understand the concept?

  30. freckles
    • one year ago
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    "Yes. So in order to find the area, you have to find the distance between the length and the width seperately. First, do (-5, 3), and (7, -6). " \[\text{ distance between these two points is } \\ \sqrt{(-5-7)^2+(3-(-6))^2} \\ =\sqrt{(-5-7)^2+(3+6)^2} \\ =\sqrt{(-12)^2+(9)^2} .. \text{ so on ... }\]

  31. anonymous
    • one year ago
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    yeah so 75

  32. iwillrektyou
    • one year ago
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    Yes. 75 is correct.

  33. anonymous
    • one year ago
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    can you help with one more?

  34. iwillrektyou
    • one year ago
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    I will try, but I am not very good at geometry, as I just started learning it. But shoot.

  35. anonymous
    • one year ago
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    |dw:1441574726192:dw| find the perimeter

  36. anonymous
    • one year ago
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    no i dont think so i think this has to do with the distance formula

  37. iwillrektyou
    • one year ago
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    Hmm..... I am not sure how to do this. Do they provide you with an ordered pair that substitutes for the variables?

  38. anonymous
    • one year ago
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    nope @freckles do you have any idea?

  39. freckles
    • one year ago
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    |dw:1441574975096:dw| the bottom we don't really have to use the distance formula for you know the distance from a to 0 is a and the distance from -a to 0 is a so the bottom length is just a+a=2a

  40. freckles
    • one year ago
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    |dw:1441575013692:dw| we have to use the distance formula for the other two sides though

  41. anonymous
    • one year ago
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    okay

  42. anonymous
    • one year ago
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    thank you guys so much for helping btw so what do we do now???

  43. iwillrektyou
    • one year ago
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    Sorry I couldn't help. I'm only in 8th grade. :(

  44. anonymous
    • one year ago
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    im in 8th too

  45. iwillrektyou
    • one year ago
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    Cool. Hopefully freckles will be able to help you do this,

  46. freckles
    • one year ago
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    distance formula for (-a,c) to (0,b) since that would be the length of that one side distance formula for (a,c) to (0,b) since that would be the length for that last side then just add all the lengths up to find the perimeter value

  47. anonymous
    • one year ago
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    can you help me in doing that?

  48. freckles
    • one year ago
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    what do you need help with exactly? entering in the values in to the formula?

  49. anonymous
    • one year ago
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    yeah just enter and then i'll solve

  50. freckles
    • one year ago
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    I will do one the distance from (-a,c) to (0,b) is: \[\sqrt{(-a-0)^2+(c-b)^2} \\ \sqrt{(-a)^2+(c-b)^2} \\ \sqrt{a^2+(c-b)^2}\] you try finding the distance from (a,c) to (0,b) now..

  51. anonymous
    • one year ago
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    so would it be sqrt (a+a)^2+(c-c)^2?

  52. freckles
    • one year ago
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    are you using the points (a,c) and (0,b)?

  53. freckles
    • one year ago
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    the change of x is a-0 not a+a the change of y is c-b not c-c

  54. anonymous
    • one year ago
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    so sqrt (a-o)^2+(c-b)^2?

  55. freckles
    • one year ago
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    yes and a-0 is just a

  56. freckles
    • one year ago
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    |dw:1441575476337:dw| \[\text{ so the distance between } (-a,c) \text{ and } (a,c) \text{ is } 2a \\ \text{ and the distance between } (a,c) \text{ and } (0,b) \text{ is } \sqrt{a^2+(c-b)^2} \\ \text{ and the distance between } (-a,c) \text{ and } (0,b) \text{ is } \sqrt{a^2+(c-b)^2}\] now just add up all 3 distances to find the perimeter

  57. anonymous
    • one year ago
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    so 2 sqrt (a^2+ (c-b)^2 +2a

  58. freckles
    • one year ago
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    yes: \[2a+2 \sqrt{a^2+(c-b)^2}\]

  59. anonymous
    • one year ago
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    thats not an answer choice

  60. anonymous
    • one year ago
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    the answer choices are 2a sqrt a^2-(c-b)^2 or 2a sqrt a^2+(c+b)^2

  61. freckles
    • one year ago
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    \[2a+2 \sqrt{a^2+(c-b)^2} \\ \text{ is the same as } 2a+2 \sqrt{a^2+(b-c)^2} \\ \text{ which is the same as } 2a+2\sqrt{(b-c)^2+a^2} \\ \text{ this is the same as } 2\sqrt{(b-c)^2+a^2}+2a \\ \text{ there is a lot of other ways \to express this }\]

  62. freckles
    • one year ago
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    you can also factor out the 2... \[2(\sqrt{(b-c)^2+a^2}+a)\]

  63. anonymous
    • one year ago
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    but thats not even a choice

  64. freckles
    • one year ago
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    it is probably a choice but it is just written a bit different as I said there is a few different ways to express that same answer

  65. anonymous
    • one year ago
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    |dw:1441575733104:dw| these are my choices

  66. freckles
    • one year ago
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    can't really read that

  67. anonymous
    • one year ago
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    |dw:1441575827490:dw|

  68. anonymous
    • one year ago
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    that second one should be a plus 2a

  69. freckles
    • one year ago
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    yeah those answers are totally wrong I don't why they put the square root over everything like that

  70. anonymous
    • one year ago
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    it shouldn't be over the 2a sorry my bad

  71. freckles
    • one year ago
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    you do know when you asked me is this the answer I said yes... you wrote so 2 sqrt (a^2+ (c-b)^2 +2a and then I said "yes \[2a+2 \sqrt{a^2+(c-b)^2}\]" and I said yes assuming you meant to write a ) at the end of the (c-b)^2 there that is 2sqrt(a^2+(c-b)^2)+2a

  72. freckles
    • one year ago
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    addition is commutative 3+2 is the same as 2+3

  73. freckles
    • one year ago
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    \[2a+2 \sqrt{a^2+(c-b)^2} \text{ is the same as } 2 \sqrt{a^2+(c-b)^2}+2a\]

  74. anonymous
    • one year ago
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    sorry its late a night im really tire

  75. anonymous
    • one year ago
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    yah but thats still not an answer?

  76. anonymous
    • one year ago
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    im not talking about the 2a or the 2, look inside the sqrt. the answer has it as a^2-(c-b)^2 or a^2+(c+b)^2

  77. freckles
    • one year ago
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    both of those are wrong though

  78. anonymous
    • one year ago
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    well that's what they have as an answer....

  79. freckles
    • one year ago
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    well I don't know what you want me to tell you

  80. freckles
    • one year ago
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    recall the distance formula is: \[\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\]

  81. freckles
    • one year ago
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    do you see there is a plus between the two square parts?

  82. freckles
    • one year ago
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    and there is a minus in between the things inside the ( )

  83. anonymous
    • one year ago
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    yeah i get it that you are right i just don't know which one to pick

  84. freckles
    • one year ago
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    the ordered pairs were definitely (0,b) and (a,c) and (-a,c) right?

  85. anonymous
    • one year ago
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    yup

  86. freckles
    • one year ago
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    the only thing I can do is guess which one they meant as the right answer but either guess I make is going to be wrong whether it is marked right or not

  87. anonymous
    • one year ago
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    should i go with the plus or the minus?

  88. freckles
    • one year ago
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    let me confirm these are the choices: \[2a+2 \sqrt{a^2-(c-b)^2} \\ 2a+2 \sqrt{a^2+(c+b)^2}\]

  89. freckles
    • one year ago
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    there are no other choices?

  90. freckles
    • one year ago
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    like you can't pick a none of these?

  91. anonymous
    • one year ago
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    the only other choices are 6a and 9a

  92. freckles
    • one year ago
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    lol I don't know go with the -

  93. freckles
    • one year ago
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    but please tell your teacher that there is a type-o

  94. anonymous
    • one year ago
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    okay

  95. anonymous
    • one year ago
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    Anyone else have any ideas?

  96. anonymous
    • one year ago
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    @freckles i think i know what the answer is

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