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FireKat97

  • one year ago

Him what would the derivative graph of this look like? ...

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  1. FireKat97
    • one year ago
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  2. FireKat97
    • one year ago
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    Hi* whoops

  3. beginnersmind
    • one year ago
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    Split it up into intervals where the function can be represented with a single formula. e.g for x in [0,1[, f(x) = 3 for x in [1,5[ , f(x) = (3/2)*(x-1) + 3 and so on. You can calculate the derivatives for these pieces easily. Remember that at points like 1,5 or 7 the derivative doesn't exist.

  4. beginnersmind
    • one year ago
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    correction: for x in [1,5[ , f(x) = -(3/2)*(x-1) + 3

  5. FireKat97
    • one year ago
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    ohh okay thanks! And I'm guessing we do a similar thing if we're working backward? So, finding the integral graph instead?

  6. beginnersmind
    • one year ago
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    I think I would just use the area definition of the integral, especially for a simple function like this. BTW, we could have solved this by remembering that the derivative of a linear function is its slope and just 'reading off' the value from the graph.

  7. FireKat97
    • one year ago
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    Okay I think I get it, thanks :)

  8. beginnersmind
    • one year ago
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    No problem :)

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