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shaniehh
 one year ago
Help Me Simplify the expression
shaniehh
 one year ago
Help Me Simplify the expression

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iwillrektyou
 one year ago
Best ResponseYou've already chosen the best response.0What is the problem?

iwillrektyou
 one year ago
Best ResponseYou've already chosen the best response.0o_O that's hard, sorry, I'm not up to that yet. :(

shaniehh
 one year ago
Best ResponseYou've already chosen the best response.0and rewrite it in rational exponent form

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.0Okay, you basically need to know 3 rules: \(\Large\color{black}{ \displaystyle x^{\color{red}{\rm a}} \times x^{\color{blue}{\rm b}}=x^{\color{red}{\rm a}+\color{blue}{\rm b}}\\[0.5em] }\) \(\Large\color{black}{ \displaystyle x^{\color{red}{\rm a}} \div x^{\color{blue}{\rm b}}=x^{\color{red}{\rm a}\color{blue}{\rm b}}\\[0.5em] }\) \(\Large\color{black}{ \displaystyle \sqrt[\color{blue}{\rm b}]{x^{\color{red}{\rm a}}}= x^{\color{red}{\rm a}/\color{blue}{\rm b}} }\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm actaully... .I kinda miss a couple of fellows, the 3 and 4 at the bottom... lemme rewrite it a bit in a sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm \(\large { \cfrac{x^{\frac{2}{3}}\cdot 24y\cdot \sqrt[4]{y^3}}{3x^2\cdot 4\sqrt[3]{x^2}} \\ \quad \\ a^{\frac{{\color{blue} n}}{{\color{red} m}}} \implies \sqrt[{\color{red} m}]{a^{\color{blue} n}} \qquad \qquad \sqrt[{\color{red} m}]{a^{\color{blue} n}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}}\qquad thus \\ \quad \\ \cfrac{x^{\frac{2}{3}}\cdot 24y\cdot \sqrt[4]{y^3}}{3x^2\cdot 4\sqrt[3]{x^2}}\implies \cfrac{x^{\frac{2}{3}}\cdot 24y\cdot y^{\frac{3}{4}}}{3x^2\cdot 4x^{\frac{2}{3}}}\qquad and\ then \\ \quad \\ a^{\frac{{\color{blue} n}}{{\color{red} m}}} = \cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}} \implies \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}}\qquad\qquad % radical denominator \cfrac{1}{\sqrt[{\color{red} m}]{a^{\color{blue} n}}}= \cfrac{1}{a^{\frac{{\color{blue} n}}{{\color{red} m}}}}\implies a^{\frac{{\color{blue} n}}{{\color{red} m}}} \qquad thus \\ \quad \\ \cfrac{x^{\frac{2}{3}}\cdot 24y^1\cdot y^{\frac{3}{4}}}{3^1x^2\cdot 4^1x^{\frac{2}{3}}}\implies x^{\frac{2}{3}}\cdot 24y^1\cdot y^{\frac{3}{4}}\cdot 3^{1}x^{2}\cdot 4^{1}x^{\frac{2}{3}} \\ \quad \\ \implies \cfrac{x^{\frac{2}{3}\cdot}\cdot x^{2}\cdot x^{\frac{2}{3}}\cdot 24y^1\cdot y^{\frac{3}{4}\cdot } }{3^1\cdot 4^1} }\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0anyhow, so use the samebase exponent rule and see what you can cancel out from the fraction

shaniehh
 one year ago
Best ResponseYou've already chosen the best response.0It says rewrite it in rational exponent form @jdoe0001

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, take a look, is all in rational exponents :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you just need to simplify it
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