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anonymous
 one year ago
I really need help with this please. :)
Here is a picture of the problem:
https://cdn.ple.platoweb.com/EdAssets/2aa74bea51264416af45cb620a392471?ts=635545843843870000
If a = 24 mm, c = 26 mm, and m∠B = 33°, what is the approximate area of ABC?
1. 261.67 mm2
2. 54.46 mm2
3. 169.93 mm2
4. 339.85 mm2
anonymous
 one year ago
I really need help with this please. :) Here is a picture of the problem: https://cdn.ple.platoweb.com/EdAssets/2aa74bea51264416af45cb620a392471?ts=635545843843870000 If a = 24 mm, c = 26 mm, and m∠B = 33°, what is the approximate area of ABC? 1. 261.67 mm2 2. 54.46 mm2 3. 169.93 mm2 4. 339.85 mm2

This Question is Closed

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1This is a right triangle?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Ok, then you can use the Pythagorean theorem to find the side b.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I would do that, but it is a degree instead of a number.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I am saying to use the `. a² + b² = c² . `

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay. Thank you so much!

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1we aren'tdone yet, are we?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Did you find the side b?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1(It will be a precise, natural number, answer)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Ok, sure, take your time:)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Oh, very good. that is right!

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441584583951:dw

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1So you can already tell which choice is closer to the area.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1441585425017:dw

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I wonder that they do not have the answer choice for that....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, the test makers didn't put the correct choice on it?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1No, I think it is rather our mistake that we assumed that your triangle is a right triangle.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so how would we solve this now?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I think we need to apply the law of cosines. \(b^2=a^2+c^22ac{\rm Cos}(B)\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0have you covered the law of cosines yet?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not yet, but this is supposed to be a Algebra 1 study.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm so.. haemm I think is safe to assume then, that is a right triangle

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1This is a good link. mathisfun is always easy to read:)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1yes jdoe, I assumed that the first I encountered it, but there is no option of 120.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well, right... I'd use the law of cosines, but if your teacher hasn't covered, there's no sense in giving you this exericse yet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for the link, I will check it out.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0law of cosines and Heron's formula to get the area then again, you may not have covered heron's formula either you might think the formula has a two long legs, but it doesn't =)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(b^2=c^2+a^22(a)(c){\rm Cos}(B)\) \(b^2=26^2+24^22(24)(26){\rm Cos}(33)\) \(b=\sqrt{26^2+24^22(24)(26){\rm Cos}(33)}=14.33\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441585266641:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 171.96 as the area, but that is not one of the answers either.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1I am trying to find every thing in the triangle, perhaps, before doing area.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\sin(33)/14.33{~~}={~~}\sin(C)/26\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1dw:1441585636236:dw

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1So the height is less that 14, but not much less than 14.33. We can guess it is 12, then it is approaches choice A.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1(That is if you want to just approximate the area. But we can try to find the height.... which is a lot of sweating)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so is this Algebra, it seems more like Geometry to me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you guys so much. Have a great day. :)
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