anonymous
  • anonymous
help me solve this equation please? will medal
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\left| x+1 \right|-3<4\]
anonymous
  • anonymous
My answer was x>6
jim_thompson5910
  • jim_thompson5910
|dw:1441587101373:dw|

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anonymous
  • anonymous
I'm sorry, it was x<7
jim_thompson5910
  • jim_thompson5910
This is not an equation. It's an inequality The first step is to add 3 to both sides |dw:1441587163774:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1441587178859:dw|
jim_thompson5910
  • jim_thompson5910
so we're left with `|x+1| < 7`
jim_thompson5910
  • jim_thompson5910
now you'll use the rule If \(\Large |x| < k\) then \(\Large -k < x < k\) where k is a positive number
anonymous
  • anonymous
okay
jim_thompson5910
  • jim_thompson5910
so in this case, that rule makes `|x+1| < 7` turn into `-7 < x+1 < 7`
anonymous
  • anonymous
whats our next step?
jim_thompson5910
  • jim_thompson5910
|dw:1441587371735:dw|
jim_thompson5910
  • jim_thompson5910
next we subtract 1 from all sides to fully isolate x |dw:1441587398846:dw|
jim_thompson5910
  • jim_thompson5910
the '1's in the middle cancel since they add to 0 |dw:1441587429310:dw|
anonymous
  • anonymous
-6
jim_thompson5910
  • jim_thompson5910
-7 - 1 is not equal to -6
anonymous
  • anonymous
on a number line would that look like this?
anonymous
  • anonymous
The draw function isnt working for me v.v
anonymous
  • anonymous
there would be an open circle at six and the arrow would go to the left continuously?
jim_thompson5910
  • jim_thompson5910
-7 - 1 = -8 instead think of it as "you're seven dollars in debt. You buy something worth 1 dollar. So you're now 8 dollars in debt"
anonymous
  • anonymous
Or would it stop at 8?
jim_thompson5910
  • jim_thompson5910
`-7 < x+1 < 7` becomes `-8 < x < 6`
jim_thompson5910
  • jim_thompson5910
|dw:1441587719085:dw|
jim_thompson5910
  • jim_thompson5910
here's what `-8 < x < 6` looks like |dw:1441587737649:dw| open circle at -8 open circle at 6 shading in between the open circles (do NOT fill in the open circles)
anonymous
  • anonymous
Thank you!
jim_thompson5910
  • jim_thompson5910
you're welcome

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