anonymous
  • anonymous
a coffee company wants a new flavor of Cajun coffee. how many pounds of coffee worth $9 a pound should be added to 30 pounds of coffee worth $3 a pound to get a mixture worth $7 a pound?
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
not impossible though we need a variable for the number of pounds of $9 coffee needed you pick it
anonymous
  • anonymous
um ... x

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anonymous
  • anonymous
ok fine
anonymous
  • anonymous
and you already have 30 pounds of coffee worth $3 a pound for a total cost of \($3\times 30=$90\)
anonymous
  • anonymous
the \(x\) pounds of coffee at $9 will cost \(9x\) dollars for a total cost of \[9x+90\]dollars
anonymous
  • anonymous
when you add your \(x\) pounds of coffee to the 30 pounds of coffee you will have \(30+x\) pounds of coffee that you want to be worth $7 a pound set \[9x+90=7(30+x)\] and solve for \(x\)
anonymous
  • anonymous
correct
anonymous
  • anonymous
x=60

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