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anonymous

  • one year ago

a coffee company wants a new flavor of Cajun coffee. how many pounds of coffee worth $9 a pound should be added to 30 pounds of coffee worth $3 a pound to get a mixture worth $7 a pound?

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    not impossible though we need a variable for the number of pounds of $9 coffee needed you pick it

  3. anonymous
    • one year ago
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    um ... x

  4. anonymous
    • one year ago
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    ok fine

  5. anonymous
    • one year ago
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    and you already have 30 pounds of coffee worth $3 a pound for a total cost of \($3\times 30=$90\)

  6. anonymous
    • one year ago
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    the \(x\) pounds of coffee at $9 will cost \(9x\) dollars for a total cost of \[9x+90\]dollars

  7. anonymous
    • one year ago
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    when you add your \(x\) pounds of coffee to the 30 pounds of coffee you will have \(30+x\) pounds of coffee that you want to be worth $7 a pound set \[9x+90=7(30+x)\] and solve for \(x\)

  8. anonymous
    • one year ago
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    correct

  9. anonymous
    • one year ago
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    x=60

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