anonymous
  • anonymous
evaluate the expression for the given value of the variable
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
\[\left| -4b-8 \right|+\left| \left| -1-b ^{2} \right| \right|+2b ^{3} \]
anonymous
  • anonymous
b=-2
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle \left| -4b-8 \right|+\left| -1-b ^{2} \right|+2b ^{3} }\) you mean like this?

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SolomonZelman
  • SolomonZelman
without dobule bars.
SolomonZelman
  • SolomonZelman
double* bars
anonymous
  • anonymous
yes
SolomonZelman
  • SolomonZelman
Then plug in -2 for b. \(\large\color{black}{ \displaystyle \left| -4(-2)-8 \right|+\left| -1-(-2) ^{2} \right|+2(-2) ^{3} }\)
anonymous
  • anonymous
my final answer is 13
SolomonZelman
  • SolomonZelman
I think that is incorrect.
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle \left| -4(-2)-8 \right|+\left| -1-(-2) ^{2} \right|+2(-2) ^{3} }\) \(\large\color{black}{ \displaystyle \left| 8-8 \right|+\left| -1-(-2) ^{2} \right|+2(-2) ^{3} }\) \(\large\color{black}{ \displaystyle \left| 0 \right|+\left| -1-(-2) ^{2} \right|+2(-2) ^{3} }\) \(\large\color{black}{ \displaystyle \left| -1-(-2) ^{2} \right|+2(-2) ^{3} }\)
SolomonZelman
  • SolomonZelman
\(\large\color{black}{ \displaystyle \left| -1-(-2) ^{2} \right|+2(-2) ^{3} }\) \(\large\color{black}{ \displaystyle \left| -1-4 \right|+2(-2) ^{3} }\) \(\large\color{black}{ \displaystyle \left| -5 \right|+2(-2) ^{3} }\) \(\large\color{black}{ \displaystyle 5+2(-2) ^{3} }\) \(\large\color{black}{ \displaystyle 5+2(-8) }\)
SolomonZelman
  • SolomonZelman
and on...
SolomonZelman
  • SolomonZelman
and you then get a negative number, that I will give you.
anonymous
  • anonymous
@SolomonZelman would you add 5 and 2 and then multiply 7 by -8
anonymous
  • anonymous
@SolomonZelman and the answer would be -56?
SolomonZelman
  • SolomonZelman
You first multiply.
SolomonZelman
  • SolomonZelman
So it is `(-2)•8` And only then, you add 5
anonymous
  • anonymous
-11?
SolomonZelman
  • SolomonZelman
Yes
anonymous
  • anonymous
thank you
SolomonZelman
  • SolomonZelman
good job

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