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anonymous

  • one year ago

i need help plss. im not sure how to find the average rate. For f(x) = 0.01(2)x, find the average rate of change from x = 2 to x = 10. 1.275 8 10.2 10.24

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  1. jim_thompson5910
    • one year ago
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    the function is this? \[\LARGE f(x) = 0.01(2)^x\]

  2. anonymous
    • one year ago
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    yes

  3. jim_thompson5910
    • one year ago
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    are you able to find the value of f(2) and f(10) ?

  4. jim_thompson5910
    • one year ago
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    let me know what you get for those values or let me know if you aren't sure how to find the function values

  5. anonymous
    • one year ago
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    im not even sure how to find the function values.. i get all mixed up when it comes to trying to find the answers to these type of questions.

  6. jim_thompson5910
    • one year ago
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    what you do is replace every x value with the input in question so say you wanted to find f(2) replace every x with 2 \[\LARGE f(\color{red}{x}) = 0.01(2)^\color{red}{x}\] \[\LARGE f(\color{red}{2}) = 0.01(2)^\color{red}{2}\] \[\LARGE f(2) = ???\]

  7. jim_thompson5910
    • one year ago
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    at this point, you use a calculator to compute `0.01*(2)^2` you can use this calculator if you don't have one http://web2.0calc.com/

  8. anonymous
    • one year ago
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    i got 0.04 @jim_thompson5910

  9. jim_thompson5910
    • one year ago
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    me too

  10. jim_thompson5910
    • one year ago
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    so f(2) = 0.04

  11. jim_thompson5910
    • one year ago
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    what is the value of f(10) ?

  12. anonymous
    • one year ago
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    100,000,000 ? ._.

  13. jim_thompson5910
    • one year ago
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    way too big

  14. jim_thompson5910
    • one year ago
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    did you type in `0.01*(2)^10` ?

  15. anonymous
    • one year ago
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    yes

  16. jim_thompson5910
    • one year ago
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    which calculator are you using?

  17. anonymous
    • one year ago
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    i got 10.24 this time.. i made a mistake

  18. jim_thompson5910
    • one year ago
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    that's ok

  19. jim_thompson5910
    • one year ago
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    now you compute \[\large \frac{f(b)-f(a)}{b-a} = \frac{f(10)-f(2)}{10-2} = \frac{10.24 - 0.04}{10-2} = ??\]

  20. anonymous
    • one year ago
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    it equals 1.275

  21. jim_thompson5910
    • one year ago
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    yep, that's your avg rate of change

  22. anonymous
    • one year ago
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    thank you so much for your help! :)

  23. jim_thompson5910
    • one year ago
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    you're welcome

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