## anonymous one year ago i need help plss. im not sure how to find the average rate. For f(x) = 0.01(2)x, find the average rate of change from x = 2 to x = 10. 1.275 8 10.2 10.24

1. jim_thompson5910

the function is this? $\LARGE f(x) = 0.01(2)^x$

2. anonymous

yes

3. jim_thompson5910

are you able to find the value of f(2) and f(10) ?

4. jim_thompson5910

let me know what you get for those values or let me know if you aren't sure how to find the function values

5. anonymous

im not even sure how to find the function values.. i get all mixed up when it comes to trying to find the answers to these type of questions.

6. jim_thompson5910

what you do is replace every x value with the input in question so say you wanted to find f(2) replace every x with 2 $\LARGE f(\color{red}{x}) = 0.01(2)^\color{red}{x}$ $\LARGE f(\color{red}{2}) = 0.01(2)^\color{red}{2}$ $\LARGE f(2) = ???$

7. jim_thompson5910

at this point, you use a calculator to compute 0.01*(2)^2 you can use this calculator if you don't have one http://web2.0calc.com/

8. anonymous

i got 0.04 @jim_thompson5910

9. jim_thompson5910

me too

10. jim_thompson5910

so f(2) = 0.04

11. jim_thompson5910

what is the value of f(10) ?

12. anonymous

100,000,000 ? ._.

13. jim_thompson5910

way too big

14. jim_thompson5910

did you type in 0.01*(2)^10 ?

15. anonymous

yes

16. jim_thompson5910

which calculator are you using?

17. anonymous

i got 10.24 this time.. i made a mistake

18. jim_thompson5910

that's ok

19. jim_thompson5910

now you compute $\large \frac{f(b)-f(a)}{b-a} = \frac{f(10)-f(2)}{10-2} = \frac{10.24 - 0.04}{10-2} = ??$

20. anonymous

it equals 1.275

21. jim_thompson5910

yep, that's your avg rate of change

22. anonymous

thank you so much for your help! :)

23. jim_thompson5910

you're welcome