## anonymous one year ago What is the length of side c to the nearest tenth of a foot?

1. anonymous

2. steve816

Use the Pythagorean theorem $a^2+b^2=c^2$

3. steve816

$400^2+900^2=c^2$ To simplify things, we're going to divide by 100 to get this $4^2+9^2=c^2$ $16+81=c^2$ $97=c^2$ $c=\sqrt{97}$ $c \approx 9.849$ Since we divided this by 100, we have to multiply by 100, so the answer would be $984.9$ feet

4. steve816

Hope this helps buddy!

5. anonymous

@steve816 Thank you! Now what if I had to find angle a with the same information?

6. steve816

Then you would use a little bit of trigonometry!

7. anonymous

@steve816 Is angle a what is known as theta if I'm not mistaken?