## anonymous one year ago help wanted will fan and medal....

1. anonymous

2. anonymous

3. anonymous

4. anonymous

@amistre64

5. anonymous

@Bee_see @mathmate @mathmath333 @kropot72

6. Bee_see

In the first problem, work on the numerator part first. Make them have the same denominator.

7. Bee_see

|dw:1441667474814:dw|

8. Bee_see

what's missing on the left side? What's missing on the right side? You want only y to be on the denominator

9. Bee_see

do you still need help?

10. anonymous

11. Bee_see

For the first problem, make the denominator the same on the numerator...so: |dw:1441672733625:dw|

12. Bee_see

|dw:1441672797727:dw|

13. Bee_see

remember that when you are adding or subtracting fractions, the fractions must have the same denominator. something like: 2/7 + 1/7 = 3/7

14. Bee_see

You have to ask yourself what the one side has that the other doesn't and you add the missing item on the top and bottom

15. Bee_see

When you are dividing fractions, you take the denominator, place it besides the numerator, flip it, and multiply...so....like this: |dw:1441673291161:dw|

16. Bee_see

|dw:1441673720939:dw|

17. anonymous

Invert the denominator, multiply the numerator by the result and then simplify.$\frac{1}{7} (3 x) \left(\frac{4 x}{y}+x\right)=\frac{12 x^2}{7 y}+\frac{3 x^2}{7}=\frac{3 x^2 (y+4)}{7 y}$

18. Bee_see

in the 2nd question., cross multiply.

19. Bee_see

|dw:1441674540603:dw|