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anonymous
 one year ago
help wanted will fan and medal....
anonymous
 one year ago
help wanted will fan and medal....

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Bee_see @mathmate @mathmath333 @kropot72

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0In the first problem, work on the numerator part first. Make them have the same denominator.

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0what's missing on the left side? What's missing on the right side? You want only y to be on the denominator

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0do you still need help?

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0For the first problem, make the denominator the same on the numerator...so: dw:1441672733625:dw

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0remember that when you are adding or subtracting fractions, the fractions must have the same denominator. something like: 2/7 + 1/7 = 3/7

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0You have to ask yourself what the one side has that the other doesn't and you add the missing item on the top and bottom

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0When you are dividing fractions, you take the denominator, place it besides the numerator, flip it, and multiply...so....like this: dw:1441673291161:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Invert the denominator, multiply the numerator by the result and then simplify.\[\frac{1}{7} (3 x) \left(\frac{4 x}{y}+x\right)=\frac{12 x^2}{7 y}+\frac{3 x^2}{7}=\frac{3 x^2 (y+4)}{7 y} \]

Bee_see
 one year ago
Best ResponseYou've already chosen the best response.0in the 2nd question., cross multiply.
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