Saylilbaby
  • Saylilbaby
help wanted will fan and medal....
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Saylilbaby
  • Saylilbaby
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Saylilbaby
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  • Saylilbaby
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Saylilbaby
  • Saylilbaby
@amistre64
Saylilbaby
  • Saylilbaby
@Bee_see @mathmate @mathmath333 @kropot72
Bee_see
  • Bee_see
In the first problem, work on the numerator part first. Make them have the same denominator.
Bee_see
  • Bee_see
|dw:1441667474814:dw|
Bee_see
  • Bee_see
what's missing on the left side? What's missing on the right side? You want only y to be on the denominator
Bee_see
  • Bee_see
do you still need help?
Saylilbaby
  • Saylilbaby
@radar
Bee_see
  • Bee_see
For the first problem, make the denominator the same on the numerator...so: |dw:1441672733625:dw|
Bee_see
  • Bee_see
|dw:1441672797727:dw|
Bee_see
  • Bee_see
remember that when you are adding or subtracting fractions, the fractions must have the same denominator. something like: 2/7 + 1/7 = 3/7
Bee_see
  • Bee_see
You have to ask yourself what the one side has that the other doesn't and you add the missing item on the top and bottom
Bee_see
  • Bee_see
When you are dividing fractions, you take the denominator, place it besides the numerator, flip it, and multiply...so....like this: |dw:1441673291161:dw|
Bee_see
  • Bee_see
|dw:1441673720939:dw|
anonymous
  • anonymous
Invert the denominator, multiply the numerator by the result and then simplify.\[\frac{1}{7} (3 x) \left(\frac{4 x}{y}+x\right)=\frac{12 x^2}{7 y}+\frac{3 x^2}{7}=\frac{3 x^2 (y+4)}{7 y} \]
Bee_see
  • Bee_see
in the 2nd question., cross multiply.
Bee_see
  • Bee_see
|dw:1441674540603:dw|

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