As θ increases from 0° to 90°, the value of cos θ tends toward which of the following? Answers available: 0 and 1. (Putting pos/neg infinity is wrong so I just need to decide which).

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

As θ increases from 0° to 90°, the value of cos θ tends toward which of the following? Answers available: 0 and 1. (Putting pos/neg infinity is wrong so I just need to decide which).

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

|dw:1441598341152:dw|
The cosine of an angle is the x-coordinate of the point of intersection of the terminal side of the angle and the unit circle.
|dw:1441598453980:dw|

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Is the answer 0?
When theta = 0 deg, cos(theta) = 1, since the x-coordinate of the point of intersection of the terminal side of of a zero-degree angle (in standard position) and the unit circle is 1.
I mean, the x-values are steadily decreasing so I assumed 0, but I am just making sure.
Correct.
Thank you :)
|dw:1441598614600:dw|
As theta goes from 0 deg to 90 deg, the x-coordinate goes from 1 to 0.
You're welcome.
@mathstudent55 could you help me with this one as well? cos θ = 1/2 and θ terminates in QIV. So far I have this: http://prntscr.com/8dhn18
\[\sin(\theta)=\pm\sqrt{1-\frac{1}{4}}=\pm\sqrt{\frac{3}{4}}=\pm\frac{\sqrt{3}}{2}\] Since theta is in 4th quadrant, sin will be negative \[\sin(\theta)=-\frac{\sqrt{3}}{4}\] There is a reason why you are given in which quadrant theta belongs to, so you can apply proper signs!
Thanks @Nishant_Garg :]
@Nishant_Garg \(\large \sin(\theta)=\pm\sqrt{1-\frac{1}{4}}=\pm\sqrt{\frac{3}{4}}=\pm\frac{\sqrt{3}}{2}\) \(\large \sin(\theta)=-\frac{\sqrt{3}}{\huge \color{red}{4}}\) ?

Not the answer you are looking for?

Search for more explanations.

Ask your own question