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kittiwitti1

  • one year ago

@mathstudent55 could you help me with this one as well? Thanks in advance- cos θ = 1/2 and θ terminates in QIV. So far I have this: http://prntscr.com/8dhn18 \[\text{not sure how the answer is not }\sqrt{3}\text{ as I ran through the calculations several times}\]\[\text{with the same result}\]

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  1. mathstudent55
    • one year ago
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    |dw:1441600085714:dw|

  2. mathstudent55
    • one year ago
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    |dw:1441600180465:dw|

  3. mathstudent55
    • one year ago
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    |dw:1441600191690:dw|

  4. kittiwitti1
    • one year ago
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    \[y=\sqrt{2^{2}-1^{2}}=\sqrt{4-1}=\sqrt{3}???\]

  5. mathstudent55
    • one year ago
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    What is y?

  6. kittiwitti1
    • one year ago
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    0.5 ?! Wait what?! o_o

  7. mathstudent55
    • one year ago
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    |dw:1441600242030:dw|

  8. kittiwitti1
    • one year ago
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    I thought this was a 30 degree angle so I went off that, and I double checked in case.... but apparently I had the wrong idea ...Isn't cos x/r?

  9. mathstudent55
    • one year ago
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    Your problem does state that cos(theta) = 1/2, right?

  10. mathstudent55
    • one year ago
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    You have the right idea. It's a 30-60-90 triangle. There is a 30 deg angle and a 60 deg angle.

  11. kittiwitti1
    • one year ago
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    Yes... and I got lost afterwards since the answer is not the 'obvious' root 3. e_e

  12. mathstudent55
    • one year ago
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    In this case, we are dealing witht he 60-deg angle.

  13. kittiwitti1
    • one year ago
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    I thought it was the 30 degree... (feels stupid) x_x

  14. mathstudent55
    • one year ago
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    |dw:1441600424201:dw|

  15. kittiwitti1
    • one year ago
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    Oh. Yes.

  16. kittiwitti1
    • one year ago
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    I neglected the quadrant. Sorry e_e

  17. mathstudent55
    • one year ago
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    Now notice that the y-coordinate is negative, so sine and cosecant will be negative. Since the x-coordinate is positive, the cosine and secant are positive. The tangent and cotangent are negative.

  18. kittiwitti1
    • one year ago
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    I think my issues were due to neglecting to check which quadrant I was in... I will make sure, brb

  19. mathstudent55
    • one year ago
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    |dw:1441600653106:dw|

  20. kittiwitti1
    • one year ago
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    Yup, got them right this time. Thanks for correcting my stupid mistake ^^;

  21. mathstudent55
    • one year ago
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    You're welcome.

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