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|dw:1441600085714:dw|

|dw:1441600180465:dw|

|dw:1441600191690:dw|

\[y=\sqrt{2^{2}-1^{2}}=\sqrt{4-1}=\sqrt{3}???\]

What is y?

0.5 ?! Wait what?! o_o

|dw:1441600242030:dw|

Your problem does state that cos(theta) = 1/2, right?

You have the right idea. It's a 30-60-90 triangle.
There is a 30 deg angle and a 60 deg angle.

Yes... and I got lost afterwards since the answer is not the 'obvious' root 3. e_e

In this case, we are dealing witht he 60-deg angle.

I thought it was the 30 degree... (feels stupid) x_x

|dw:1441600424201:dw|

Oh. Yes.

I neglected the quadrant. Sorry e_e

I think my issues were due to neglecting to check which quadrant I was in... I will make sure, brb

|dw:1441600653106:dw|

Yup, got them right this time. Thanks for correcting my stupid mistake ^^;

You're welcome.