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kittiwitti1
 one year ago
@mathstudent55 could you help me with this one as well?
Thanks in advance
cos θ = 1/2 and θ terminates in QIV.
So far I have this:
http://prntscr.com/8dhn18
\[\text{not sure how the answer is not }\sqrt{3}\text{ as I ran through the calculations several times}\]\[\text{with the same result}\]
kittiwitti1
 one year ago
@mathstudent55 could you help me with this one as well? Thanks in advance cos θ = 1/2 and θ terminates in QIV. So far I have this: http://prntscr.com/8dhn18 \[\text{not sure how the answer is not }\sqrt{3}\text{ as I ran through the calculations several times}\]\[\text{with the same result}\]

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441600085714:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441600180465:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441600191690:dw

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1\[y=\sqrt{2^{2}1^{2}}=\sqrt{41}=\sqrt{3}???\]

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.10.5 ?! Wait what?! o_o

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441600242030:dw

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1I thought this was a 30 degree angle so I went off that, and I double checked in case.... but apparently I had the wrong idea ...Isn't cos x/r?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Your problem does state that cos(theta) = 1/2, right?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2You have the right idea. It's a 306090 triangle. There is a 30 deg angle and a 60 deg angle.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1Yes... and I got lost afterwards since the answer is not the 'obvious' root 3. e_e

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2In this case, we are dealing witht he 60deg angle.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1I thought it was the 30 degree... (feels stupid) x_x

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441600424201:dw

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1I neglected the quadrant. Sorry e_e

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2Now notice that the ycoordinate is negative, so sine and cosecant will be negative. Since the xcoordinate is positive, the cosine and secant are positive. The tangent and cotangent are negative.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1I think my issues were due to neglecting to check which quadrant I was in... I will make sure, brb

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.2dw:1441600653106:dw

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1Yup, got them right this time. Thanks for correcting my stupid mistake ^^;
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