kittiwitti1
  • kittiwitti1
@mathstudent55 could you help me with this one as well? Thanks in advance- cos θ = 1/2 and θ terminates in QIV. So far I have this: http://prntscr.com/8dhn18 \[\text{not sure how the answer is not }\sqrt{3}\text{ as I ran through the calculations several times}\]\[\text{with the same result}\]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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mathstudent55
  • mathstudent55
|dw:1441600085714:dw|
mathstudent55
  • mathstudent55
|dw:1441600180465:dw|
mathstudent55
  • mathstudent55
|dw:1441600191690:dw|

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More answers

kittiwitti1
  • kittiwitti1
\[y=\sqrt{2^{2}-1^{2}}=\sqrt{4-1}=\sqrt{3}???\]
mathstudent55
  • mathstudent55
What is y?
kittiwitti1
  • kittiwitti1
0.5 ?! Wait what?! o_o
mathstudent55
  • mathstudent55
|dw:1441600242030:dw|
kittiwitti1
  • kittiwitti1
I thought this was a 30 degree angle so I went off that, and I double checked in case.... but apparently I had the wrong idea ...Isn't cos x/r?
mathstudent55
  • mathstudent55
Your problem does state that cos(theta) = 1/2, right?
mathstudent55
  • mathstudent55
You have the right idea. It's a 30-60-90 triangle. There is a 30 deg angle and a 60 deg angle.
kittiwitti1
  • kittiwitti1
Yes... and I got lost afterwards since the answer is not the 'obvious' root 3. e_e
mathstudent55
  • mathstudent55
In this case, we are dealing witht he 60-deg angle.
kittiwitti1
  • kittiwitti1
I thought it was the 30 degree... (feels stupid) x_x
mathstudent55
  • mathstudent55
|dw:1441600424201:dw|
kittiwitti1
  • kittiwitti1
Oh. Yes.
kittiwitti1
  • kittiwitti1
I neglected the quadrant. Sorry e_e
mathstudent55
  • mathstudent55
Now notice that the y-coordinate is negative, so sine and cosecant will be negative. Since the x-coordinate is positive, the cosine and secant are positive. The tangent and cotangent are negative.
kittiwitti1
  • kittiwitti1
I think my issues were due to neglecting to check which quadrant I was in... I will make sure, brb
mathstudent55
  • mathstudent55
|dw:1441600653106:dw|
kittiwitti1
  • kittiwitti1
Yup, got them right this time. Thanks for correcting my stupid mistake ^^;
mathstudent55
  • mathstudent55
You're welcome.

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