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kittiwitti1

  • one year ago

Find y if the point (15, y) is on the terminal side of θ and\[\cos\theta=\frac{15}{17}\](Enter your answers as a comma-separated list.) My result was \[\pm8\]but I'm told that it's the wrong answer. ッ

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  1. jchick
    • one year ago
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    Can you post your work?

  2. kittiwitti1
    • one year ago
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    \[y=\sqrt{17^{2}-15^{2}}=\sqrt{289-225}=\sqrt{64}=\pm8\]

  3. kittiwitti1
    • one year ago
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    Okay, does that help or should I do anything else?

  4. jchick
    • one year ago
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    Did you do anything else?

  5. kittiwitti1
    • one year ago
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    \[x=15,y=8,r=17\]\[\sin\theta=\frac{8}{17},\cos\theta=\frac{15}{17},\csc\theta=\frac{17}{8},\sec\theta=\frac{17}{15}\]I would have kept going but I'm not sure if I'm going in the right direction.

  6. jchick
    • one year ago
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    Yes you are in the right direction that is what I got.

  7. kittiwitti1
    • one year ago
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    It is the wrong answer apparently...

  8. jchick
    • one year ago
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    Did you submit it?

  9. jchick
    • one year ago
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    That is odd

  10. kittiwitti1
    • one year ago
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    I put \[\pm8\]Wrong answer, it says.

  11. jchick
    • one year ago
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    Wait did you have to type your answer?

  12. kittiwitti1
    • one year ago
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    Yes. (I put -8, 8)

  13. jchick
    • one year ago
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    Does it automatically correct it?

  14. kittiwitti1
    • one year ago
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    @jim_thompson5910 @ganeshie8 @Hero No, it does not.

  15. kittiwitti1
    • one year ago
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    @DanJS @dan815

  16. jchick
    • one year ago
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    Ok so your teacher said it was wrong

  17. kittiwitti1
    • one year ago
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    No, the website says I am wrong.

  18. kittiwitti1
    • one year ago
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    http://prntscr.com/8di0sp

  19. jchick
    • one year ago
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    Ok that is a auto correcting website?

  20. jchick
    • one year ago
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    So maybe you put an extra space or something?

  21. kittiwitti1
    • one year ago
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    ...No?

  22. jchick
    • one year ago
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    Ok sorry I can't help further

  23. kittiwitti1
    • one year ago
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    ...Okay thanks anyway....

  24. kittiwitti1
    • one year ago
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    @DanJS can you help? :c

  25. kittiwitti1
    • one year ago
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    ...I'm just going to repost this.

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