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kittiwitti1
 one year ago
REPOST (because the other one got too cluttered)
Find y if the point (15, y) is on the terminal side of θ and\[\cos\theta=\frac{15}{17}\](Enter your answers as a commaseparated list.)
My result was \[\pm8\]but I'm told that it's the wrong answer. ッ
what I did: \[y=\sqrt{17^{2}15^{2}}=\sqrt{289225}=\sqrt{64}=\pm8\]\[x=15,y=8,r=17\]\[\sin\theta=\frac{8}{17},\cos\theta=\frac{15}{17},\csc\theta=\frac{17}{8},\sec\theta=\frac{17}{15}\]I would have kept going but I'm not sure if I'm going in the right direction.
kittiwitti1
 one year ago
REPOST (because the other one got too cluttered) Find y if the point (15, y) is on the terminal side of θ and\[\cos\theta=\frac{15}{17}\](Enter your answers as a commaseparated list.) My result was \[\pm8\]but I'm told that it's the wrong answer. ッ what I did: \[y=\sqrt{17^{2}15^{2}}=\sqrt{289225}=\sqrt{64}=\pm8\]\[x=15,y=8,r=17\]\[\sin\theta=\frac{8}{17},\cos\theta=\frac{15}{17},\csc\theta=\frac{17}{8},\sec\theta=\frac{17}{15}\]I would have kept going but I'm not sure if I'm going in the right direction.

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kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1Please help, anyone? @DanJS @dan815 @ganeshie8 @Luigi0210

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1@undeadknight26 @radar @freckles @Zale101 I don't want to masstag but I really need help on this. e_e

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1Did I mess up anywhere?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1\(\pm 8\) looks good to me

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1Indeed but I got the "wrong answer" according to the website. I am confused. http://prntscr.com/8di5he @ganeshie8 ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1try entering 8,8 without spaces between them

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1I've done that on other problems with the same result as the original attempt... I honestly don't think it's a typo issue.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1But if you think there is no other way that it is wrong I will try it. ^^; I wanted to try this but I wasn't sure if I'd done anything wrong; hence wasting an answer submission would not be ideal.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1please take other opinions too

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1I trust your opinion though >_> yours and batman's. but he's offline

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1to me 8,8 looks is the correct answer i don't see how it can possibly go wrong..

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1Okay I'll submit it then :]

jchick
 one year ago
Best ResponseYou've already chosen the best response.0Yes I got the same thing

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1stares blankly OMFG. IT WAS THE REASON ALL ALONG

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1slams face into desk WHY IS THIS WEBSITE SO FREAKING STUPID.

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1But thanks for your time and help @ganeshie8 :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.1dumb graders, congrats! :)

kittiwitti1
 one year ago
Best ResponseYou've already chosen the best response.1lol yes. thank you very much > _ <;;
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