anonymous
  • anonymous
what is x^2/3 -64=0
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
zepdrix
  • zepdrix
\[\large\rm x^{2/3}-64=0\]Add 64,\[\large\rm x^{2/3}=64\]Now to deal with the exponent...
zepdrix
  • zepdrix
If you were dealing with something like this: \(\large\rm \sqrt[3]{x}\) you could rewrite it like this: \(\large\rm x^{1/3}\) and to undo the root, you would raise it to the third power. \(\large\rm \left(x^{1/3}\right)^{3}=x\) If I was trying to undo an exponent from something like this: \(\large\rm x^{2}\) I would take the square root of it, which is the same as applying the 1/2 power. \(\large\rm (x^2)^{1/2}=|x|\)
zepdrix
  • zepdrix
In our problem here, we kinda want to do both of those things. We want to get rid of the 2 on the x, and the 1/3 on the x. So we'll apply a 3/2 power to each side,\[\large\rm \left(x^{2/3}\right)^{3/2}=64^{3/2}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

zepdrix
  • zepdrix
\[\large\rm |x|=64^{3/2}\]\[\large\rm x=\pm 64^{3/2}\]
zepdrix
  • zepdrix
Hopefully I was reading your initial problem correctly D: It wasn't this, right? \(\large\rm \frac{x^2}{3}-64=0\)
anonymous
  • anonymous
thanks :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.