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Simplyfly
here is an example \[\huge\rm (ab)^m= a^m b^m\] so (2y)^3 = ?

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sorry, was offline
These are the answer choices
So wouldn't be A?
how?
(2y)^3 how would you simplify this ?
2 x 2 x 2=8
yes right 2 to the 3rd power and y to the 3rd power then multiply the same base when we multiply same bases we should add their exponents\[\huge\rm x^m \times x^n=x^{m+n}\]
let me know what you get
2^3 x y^3= 2y^8+3=11??
y^8 ??
\[\huge\rm (2y)^3 \times y^{-1}= 2^3y^3 \times y^{-1}\]
now multiply y^3 times y^{-1}
-1
-1 x -1 x -1
no apply the exponent rule when multiply same base we should add exponnets
? I'm sorry 8 x -1=7x x -1
no just at the exponnets \[\huge\rm 2^3\color{ReD}{y}^\color{blue}{3} \times \color{ReD}{y}^\color{blue}{-1}\] the base y is same so you can `add` their exponents
-9
how did you get 9 ?
3 x 3 x -1=-9 just the exponets
well first of all bases should be the `SAME` 2nd you should `ADD` them not multiply
2 and y are not the same bases
|dw:1441634613787:dw|
hint: \[\Large {\left( {2y} \right)^3}{y^{ - 1}} = {2^3}{y^3}{y^{ - 1}} = ...?\]
here is an example \[\huge\rm a^3 \times a^6= a^{3+6}=a^9\]

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