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freemap

  • one year ago

Please Help With My Question?

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  1. freemap
    • one year ago
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  2. freemap
    • one year ago
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    Simplyfly

  3. Nnesha
    • one year ago
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    here is an example \[\huge\rm (ab)^m= a^m b^m\] so (2y)^3 = ?

  4. freemap
    • one year ago
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    sorry, was offline

  5. freemap
    • one year ago
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    These are the answer choices

  6. freemap
    • one year ago
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    So wouldn't be A?

  7. Nnesha
    • one year ago
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    how?

  8. Nnesha
    • one year ago
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    (2y)^3 how would you simplify this ?

  9. freemap
    • one year ago
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    2 x 2 x 2=8

  10. Nnesha
    • one year ago
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    yes right 2 to the 3rd power and y to the 3rd power then multiply the same base when we multiply same bases we should add their exponents\[\huge\rm x^m \times x^n=x^{m+n}\]

  11. Nnesha
    • one year ago
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    let me know what you get

  12. freemap
    • one year ago
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    2^3 x y^3= 2y^8+3=11??

  13. Nnesha
    • one year ago
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    y^8 ??

  14. Nnesha
    • one year ago
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    \[\huge\rm (2y)^3 \times y^{-1}= 2^3y^3 \times y^{-1}\]

  15. Nnesha
    • one year ago
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    now multiply y^3 times y^{-1}

  16. freemap
    • one year ago
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    -1

  17. freemap
    • one year ago
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    -1 x -1 x -1

  18. Nnesha
    • one year ago
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    no apply the exponent rule when multiply same base we should add exponnets

  19. freemap
    • one year ago
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    ? I'm sorry 8 x -1=7x x -1

  20. Nnesha
    • one year ago
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    no just at the exponnets \[\huge\rm 2^3\color{ReD}{y}^\color{blue}{3} \times \color{ReD}{y}^\color{blue}{-1}\] the base y is same so you can `add` their exponents

  21. freemap
    • one year ago
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    -9

  22. Nnesha
    • one year ago
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    how did you get 9 ?

  23. freemap
    • one year ago
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    3 x 3 x -1=-9 just the exponets

  24. Nnesha
    • one year ago
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    well first of all bases should be the `SAME` 2nd you should `ADD` them not multiply

  25. Nnesha
    • one year ago
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    2 and y are not the same bases

  26. Nnesha
    • one year ago
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    |dw:1441634613787:dw|

  27. Michele_Laino
    • one year ago
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    hint: \[\Large {\left( {2y} \right)^3}{y^{ - 1}} = {2^3}{y^3}{y^{ - 1}} = ...?\]

  28. Nnesha
    • one year ago
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    here is an example \[\huge\rm a^3 \times a^6= a^{3+6}=a^9\]

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